Solve the inequalityfor v 4v<20

Janelle practices basketball every afternoon in the driveway each day her goal is to make four more baskets then she made the da

Alla [95]

She made 62 baskets by day 14. 4×13=52+10=62

5 0

3 years ago

PLZ HELP!!! Connor earns 24$ working every 1.5 hours. How much money would he earn after 12 hours.

luda_lava [24]

Answer:

$288

Step-by-step explanation:

hope this helps

5 0

3 years ago

Jose received $250 for his birthday from his family. He wishes to buy a motorcycle and decides to use his birthday money towards

BartSMP [9]

Answer:

He will have $276.10 available towards the down payment for his motorcycle

Step-by-step explanation:

The compound interest formula is given by:

$A = P(1 + \frac{r}{n})^{nt}$

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this problem, we have that:

$P = 250, t = 2, r = 0.05$

Compounded quarterly, so n = 12/4 = 3.

We have to find A.

$A = P(1 + \frac{r}{n})^{nt}$

$A = 250(1 + \frac{0.05}{3})^{3*2}$

$A = 276.1$

He will have $276.10 available towards the down payment for his motorcycle

8 0

3 years ago

Set Question involving real and natural numbers

Allushta [10]

Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like

(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}

√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then

(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}

A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that

(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}

I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then

(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.

N is a subset of B, so

(iv.b) N - B = N = {1, 2, 3, ...}

3 0

2 years ago

a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues