2+2+3+3+4+4+5+5+6+6+7+7+8+8+9+9+2+2
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We are told that the children from a football club are put into rows in the sports hall. When put into rows of 9 children there are 2 children left over. When put into rows of 12 children there are 2 children left over.
We will find least number of children in football club by finding LCM of 9 and 12.
Multiples of 9 are: 9, 18, 27, 36, 45, 54, 63,...
Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...
We can see that least common multiple of 9 and 12 is 36.
We are told that 2 children left over from putting them into 9 and 12 children per row. To find least number we will add 2 to 36.
Therefore, the least number of children in the football club is 38.
Given mean = 0 C and standard deviation = 1.00
To find probability that a random selected thermometer read less than 0.53, we need to find z-value corresponding to 0.53 first.
z=
So, P(x<0.53) = P(z<0.53) = 0.701944
Similarly P(x>-1.11)=P(z>-1.11) = 1-P(z<-1.11) = 0.8665
For finding probability for in between values, we have to subtract smaller one from larger one.
P(1.00<x<2.25) = P(1.00<z<2.25) = P(z<2.25)- P(z<1.00) = 0.9878 - 0.8413 = 0.1465
P(x>1.71) = P(z>1.71) = 1-P(z<1.71) = 1-0.9564 = 0.0436
P(x<-0.23 or x>0.23) = P(z<-0.23 or z>0.23) =P(z<-0.23)+P(z>0.23) = 0.409+0.409 = 0.918