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Kryger [21]
3 years ago
12

square GYTD has vertices G(-4,3), Y (0,3), T (0,-1) and D (-4, -1) square GYTD is translated 2 units left and 2 units up to prod

uce square G'YT'D' which coordinates describe the vertices of the image?
Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
ANSWER:
G’(-6,5) Y’(-2,5) T’(-2,1) D’(-6,1)

WORK OUTS:
G’=(-4-2,3+2)=(-6,5)
Y’=(0-2,3+5)=(-2,5)
T’=(0-2,-1+2)=(-2,1)
D’=(-4-2,-1+2)=(-6,1)

EXPLANATION:
Because the translation is 2 units to the left, which makes it -2(going to the right is positive and the left is negative). Then you will subtract 2 from each x value because translating right and left effects the x value of the coordinates.
You were also given that the translation is 2 units upwards ( going upwards is positive and downwards is negative) therefore the 2 will stay positive. Then you will add 2 to each y value because translating up and down effects the y value of the coordinates.
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Which problem could be solved by evaluating the expression 7 x (-3)?​
Tasya [4]

Answer:

The answer is -21

Step-by-step explanation:

To find the answer just multiply 7 by 3 and that's 21, so just add a negative sign to 21 and you get -21. I hope this helps :) please give me brainliest :)

6 0
3 years ago
Read 2 more answers
ABCD is a parallelogram. Find the values of x and y. Solve for the value of z, if z=x−y.
slava [35]

Answer:

C

Step-by-step explanation:

Parallel and opposite sides of a parallelogram are equal. Hence, we can say:

x + 30 = 2x - 10

and

2y-10 = y +10

Solving first one, we get:

x + 30 = 2x - 10

30+10 = x

x = 40

Also

2y - 10 = y + 10

y = 10 + 10

y = 20

Now, z = x - y, so

z = 40 - 20 = 20

Answer C is right.

3 0
3 years ago
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac
agasfer [191]

Answer:

a) \frac{8}{9} =0.89

b) 0.8413

Step-by-step explanation:

we know that

P(║ x -\mu║ \leq  k\sigma) \geq 1 -\frac{1}{k^2}

so, \mu = 150, \sigma = 20

k =  \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3

P(║ x -150 ║ \leq  3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}

x - N(150, 20^2)

P(X \leq 170) = 0.8413447

check

P norm = \frac{170 - 150}{20}= 0.8413447

8 0
3 years ago
water weighs about 8.34 pounds per gallon. About how many ounces per gallon is the weight of the water?
notka56 [123]
Use a conversion factor and turn pounds to ounces. 1 pound = 16 ounces so
\frac{8.34pounds}{gallon} \times \frac{16 ounces}{ 1 pound} =133.44 \frac{ounces}{gallon}
3 0
3 years ago
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