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KiRa [710]
3 years ago
15

Does anyone know this answer?? Choices- 333.50, 63.50, 153.50, 166.75

Mathematics
2 answers:
mariarad [96]3 years ago
4 0

Answer:

153.50

Step-by-step explanation:

Sum of all interior angles of a triangle is 180°.

Option(1): 333.5 is much greater than 180(sum of all angles). 333.5 + 13.25 + angle P = 180, for all +ve values of angle P.

/_P = 180° - 13.25 - 333.5 , /_P is -ve from this which is impossible(for an angle in triangle)

This is incorrect.

Option(2): As it can observed, /_ R is much greater than 90°. It means, it should be greater than 63.50°.

This is incorrect.

Option(3): 153.50 is greater than 90°. Moreover, if /_ R is 153.5, let /_P be x, then,

=> 13.25 + 153.50 + x = 180°

=> x = 13.25. , which is +ve

So we can say /_P = 153.50

Option(4): if /_ R is 153.5, let /_P be x, then,

=> 13.25 + 166.75 + x = 180°

=> x = 0 , which is impossible(as we can see It's not 0)

Incorrect.

ipn [44]3 years ago
3 0
Answer: 153.50

180-13.25-13.25 = 153.50

The two acute angles are the same so look for the obtuse.
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Since we don't know what  log_{100}20  is equal to, we will say  log_{100}20 = x

So to solve for log_{100}20 = x, you do the same thing. (convert to exponential form)

100^{x} =20

Now you will notice that both of these equations are equal to 20.

Since 20 = 20,

we can say 100^{x} = 10^{1.301}

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Step-by-step explanation:

Given

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Solving (a): (r o q)(2)

In function:

(r o g)(x) = r(g(x))

So, first we calculate g(2)

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g(2) = 4 + 5

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Next, we calculate r(g(2))

Substitute 9 for g(2)in r(g(2))

r(q(2)) = r(9)

This gives:

r(x) = \sqrt{x + 7}

r(9) = \sqrt{9 +7{

r(9) = \sqrt{16}{

r(9) = 4

Hence:

(r o g)(2) = 4

Solving (b): (q o r)(2)

So, first we calculate r(2)

r(x) = \sqrt{x + 7}

r(2) = \sqrt{2 + 7}

r(2) = \sqrt{9}

r(2) = 3

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Substitute 3 for r(2)in g(r(2))

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Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

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we know that

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the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

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substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

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step 2

Find the distance BC

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substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

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Find the distance AC

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