Select the best answer for the question.
2 answers:
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sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule,
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option
We have been given an equation . We are asked to fill in the blanks using our given equation.
The axis of symmetry will be the vertical line passing through vertex.
First of all, we will convert our given equation in standard vertex form of parabola as:
Standard vertex form of parabola: , where (h,k) is vertex of parabola.
Upon comparing our function with standard vertex form, we can see that vertex of parabola is at .
The axis of symmetry will be vertical line passing through point . The vertical line will pass through
, therefore, the axis of symmetry is
.
Since our given parabola is an upward opening parabola, so it has a minimum at . This means that parabola will intersect the x-axis at two points. Therefore, there are two real solutions for the given function.