I think it’s q12 or C hope this helped
So distribute using distributive property
a(b+c)=ab+ac so
split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24
the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24
1) Line should be parallel to y = 3x+6, so slope of this line should be =3.
y=mx +b
y=3x +b
Now we have to find b (y-intercept), using the point (-10, 2.5).
2.5 = 3*(-10)+b
b=2.5+30=32.5
y=3x + 32.5
2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.
Now we have to find b (y-intercept), using the point (-16, -11).
y=(1/4)x +b
-11=(1/4)*(-16) + b
-11 = -4 +b
b = -7
y=(1/4)x - 7
The answer would be D. It would be $42 in the end if you picked D.
Answer:
the answer is 2
Step-by-step explanation:
