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dedylja [7]
3 years ago
9

The sides of the base of a right square pyramid are 5 centimeters, and the slant height is 8 centimeters. If the sides of the ba

se and the slant height are each multiplied by 5, by what factor is the surface area multiplied?
A. 5 to 0
B. 5 to 1
C. 5 to 2
D. 5 to 3
Mathematics
2 answers:
Vinil7 [7]3 years ago
5 0

Answer:

c.answer

Step-by-step explanation:

maxonik [38]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

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where

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Part 1) First graph

we know that

The solutions or zeros of the first graph are

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The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

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therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

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