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2 years ago

What 2 square numbers have a sum of 130

Mathematics

1 answer:

postnew [5]2 years ago

6 0

130=a²+b²
130=9²+7²
81+49=130

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Which of the following solution graphs represent a "UNION"

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Answer:

I believe it's A

Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five

exis [7]

Answer:

$\dfrac{14}{29}$

Step-by-step explanation:

Let P(A) be the probability that goggle of type A is manufactured

P(B) be the probability that goggle of type B is manufactured

P(E) be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

P(A) = 30%

P(B) = 70%

P(E/A) is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

$P(A \cap E)$ will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

$P(B \cap E)$ will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

$P(E \cap A) = P(A) \times P(E/A)$

$P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%$

$P(E \cap B) = P(B) \times P(E/B)$

$P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%$

$P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%$

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

$P(B/E) = \dfrac{P(E \cap B)}{P(E)}$

$\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}$

So, the required probability is $\dfrac{14}{29}.$

7 0

3 years ago

Triangle QRS is dilated according to the rule DO,2 (x,y).

pogonyaev

I found the correct image that accompanies this problem and edited it with my answers.. Pls. see attachment.

Based on the attachment, the correct statements are:

1) DO,2 (x,y) = (2x, 2y)
2) Side Q'S' lies on a line with a slope of -1.
Q'(-6,6) S'(-2,2)
m = y1 - y2 / x1 - x2
m = 6 - 2 / -6 - (-2)
m = 4 / -4
m = -1
5) The distance from Q' to the origin is twice the distance from Q to the origin.