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3 years ago

5

Assuming boys and girls are equally likely, find the probability of a couple having a baby boy when their third child is born,

given that the first two children were both boys

1 answer:

posledela3 years ago

8 0

50% because the first two children have no effect on the third one

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X=<br> - 6 2/3<br> - 9<br> - 12<br> please help asap

Nastasia [14]

Answer:

Step-by-step explanation:

x=12

4 0

3 years ago

I’m pretty sure the correct answer is A, but I’d like to double check

irinina [24]

3x² - 4 → A

(f + g)(x) = f(x) + g(x) = 2x² + 3 + x² - 7 = 3x² - 4

8 0

4 years ago

Can someone please simplify these.

Annette [7]

Answer:

9 is -4b with the little thing on top is 4.

Step-by-step explanation: hope that helped a little and could i get a brainlist thing...

10 is

y with the thing on top is 5

fraction with a "-"

2

3 0

4 years ago

3X squared plus 2X equals -4 number of solutions

PIT_PIT [208]

Answer:

The given equation has two solutions i.e $\frac{-1+\sqrt{13} }{3}$ , $\frac{-1-\sqrt{13} }{3}$

Step-by-step explanation:

The given expression as :

3 x² + 2 x - 4

For the quadratic equation in the form of a x² + b x + c , the value of x

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, x = $\frac{-2\pm \sqrt{2^{2}-4\times 3\times (-4)}}{2\times 3}$

Or, x = $\frac{-2\pm \sqrt{4 + 48}}{6}$

or, x = $\frac{-2\pm \sqrt{52}}{6}$

∴ x = $\frac{-1\pm \sqrt{13}}{3}$

Or, x = $\frac{-1+\sqrt{13} }{3}$ , $\frac{-1-\sqrt{13} }{3}$

Hence The given equation has two solutions i.e $\frac{-1+\sqrt{13} }{3}$ , $\frac{-1-\sqrt{13} }{3}$ Answer

7 0

3 years ago

Explain how finding 4×30 he can help you find 4×5384 then find the both products

wlad13 [49]

You can do this by doing 4 x 384, and you also want to find 4 x 5384 is then all you have to do is multiply the product of that by 5,000. Or to make life easier, do 5 times the product, and then add 3 zeros to the answer.

3 0

3 years ago