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laiz [17]
3 years ago
6

If you have 2 water molecules together, would you expect them to sit "hydrogen by hydrogen" or "hydrogen to oxygen"? Why?

Chemistry
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

"hydrogen to oxygen"

Explanation:

Hydrogen bonds are formed when hydrogen is bonded to highly electronegative element such as Chlorine, fluorine, oxygen etc.

In hydrogen bonding, the hydrogen atom of one molecule of water is attracted to the oxygen atom of another molecule of water via permanent dipole-dipole interaction.

Hence, If you have 2 water molecules together, they always sit "hydrogen to oxygen" as a result of dipole - dipole interaction and  hydrogen bonding between water molecules.

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What is the [H3O+] of a solution with a pH of 8.43?
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Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha
Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles

The chemical equation for the reaction of NaI and lead chlorate follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = \frac{1}{2}\times 0.04=0.02mol of lead iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g

Hence, the mass of lead iodide produced is 9.22 grams

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Question 12 of 35
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