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3 years ago

If you have 2 water molecules together, would you expect them to sit "hydrogen by hydrogen" or "hydrogen to oxygen"? Why?

Chemistry

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer:

"hydrogen to oxygen"

Explanation:

Hydrogen bonds are formed when hydrogen is bonded to highly electronegative element such as Chlorine, fluorine, oxygen etc.

In hydrogen bonding, the hydrogen atom of one molecule of water is attracted to the oxygen atom of another molecule of water via permanent dipole-dipole interaction.

Hence, If you have 2 water molecules together, they always sit "hydrogen to oxygen" as a result of dipole - dipole interaction and hydrogen bonding between water molecules.

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An electrochemical cell is powered by the half reactions shown below.

nikitadnepr [17]

Ag+(aq) + e– → Ag(s) Eo = +0.80 V
Pb2+(aq) + 2e– → Pb(s) Eo = –0.13 V

=>

2Ag+(aq) + 2e– → 2Ag(s) Eo = +0.80 V

Pb(s) → Pb2+(aq) + 2e– - Eo = – (-0.13 V) = +0.13 V
----------------------------------

2Ag(+) (aq) + Pb(s) -------> 2Ag(s) + Pb(2+)


E cell = E0 cathode – Eo anode = 0.80V - (- 0.13V) = 0.80V + 0.13V = 0.93V.

Answer: + 0.93V

5 0

3 years ago

Two of the simplest compounds containing just carbon and hydrogen are methane and ethane. Methane contains 0.3357 g of hydrogen

Andreyy89

Let the ratio of grams of hydrogen per gram of carbon in methane be M, we know that:
M = 0.3357 g / 1 g

Next, lets represent the grams of hydrogen per gram of carbon in ethane be E. The final piece of information we have is:

M / E = 4/3

If we cross multiply,

3M = 4E

Now, substituting the value of M from earlier and solving for E,

E = (3 * 0.3357) / 4
E = 0.2518

There are 0.2518 grams of hydrogen per gram of carbon in ethane.

5 0

3 years ago

Jamie completes the following steps in an experiment to investigate how temperature affects how fast something will rust in wate

JulijaS [17]

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers

study figure 10-3. how much nitrogen-14 will be produced from a 200-g sample of carbon 14 after 17,190 years

Amanda [17]

For this problem, we use the formula for radioactive decay which is expressed as follows:

An = Aoe^-kt

where An is the amount left after time t, Ao is the initial amount and k is a constant.

We calculate as follows:

An = Aoe^-kt
0.5 = e^-k(5730)
k = 1.21x10^-4

An = Aoe^-kt
An = 200e^-1.21x10^-4(17190)
An = 25

Therefore, about 175g is produced.

8 0

4 years ago

Identify the missing species in each nuclear equation. Replace the question marks with the appropriate integer or symbol. Be410⟶

astraxan [27]

Answer:

1. ¹⁰₄Be ---> ¹⁰₅B + ⁰₋₁β

2. ³⁴₁₄Be ---> ³⁴₁₅P + ⁰₋₁β

3. ¹⁹²₇₈Pt -----> ¹⁹⁰₇₆Os + ⁴₂α

4. ²⁸₁₂Mg ---> ²⁸₁₃Al + ⁰₋₁β

Explanation:

1. In the first equation, Beryllium-10 isotope undergoes beta-decay, emitting a beta-particle to form boron-10 isotope. The balanced nuclear equation is given below:

¹⁰₄Be ---> ¹⁰₅B + ⁰₋₁β

2. In this reaction, silicon-34 isotope undergoes beta-decay, emitting a beta-particle to form phosphorus-34 isotope. The balanced nuclear equation is given below:

³⁴₁₄Be ---> ³⁴₁₅P + ⁰₋₁β

3. In this equation, platinum-192 isotope undergoes alpha-particle decay emitting an alpha-particle to form osmium-190 isotope. The balanced nuclear equation is given below:

¹⁹²₇₈Pt -----> ¹⁹⁰₇₆Os + ⁴₂α

4. In this equation, magnesium-28 isotope undergoes beta-decay, emitting a beta-particle to form aluminum-28 isotope. The balanced nuclear equation is given below:

²⁸₁₂Mg ---> ²⁸₁₃Al + ⁰₋₁β

8 0

3 years ago