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Xelga [282]
3 years ago
10

Is anyone good at chemistry if so can someone help me please ? (NO LINKS)

Chemistry
1 answer:
antiseptic1488 [7]3 years ago
6 0

Since pH + pOH = 14, given a pOH of 4.53, our pH would be 14 - 4.53 = 9.47. And since the pH is greater than 7, this solution is basic. So, the correct answer choice would be D.

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The key enzyme in the regulation of the citric acid cycle is:.
bixtya [17]

The key enzyme in the regulation of the citric acid cycle is citrate synthase. It functions in the mitochondria.

<h3>Citrate synthase and cellular respiration </h3>

Cellular respiration is a series of reactions that produce ATP by using the energy stores in the chemical bonds of foods.

Cellular respiration is divided into glycolysis, the citric-acid cycle and oxidative phosphorylation.

Citrate synthase is an enzyme found in the mitochondrial matrix, which is involved in the citric acid cycle.

Learn more about cellular respiration here:

brainly.com/question/2809259

3 0
2 years ago
How do the properties of compounds often compare with the properties of the elements that make them
const2013 [10]
The properties of a compound are nothing like the properties of th elements that combine to make it.


sodium chloride,NaCl, table salt, is a white cubic crystal, stable ionic compound, soluble in water
sodium is a soft metal, very reactive with water and air
chlorine is a yellow green gas that is poisonous and very reactive.

carbon dioxide, CO2, is a clear, colorless gas that puts out fires, plants use but we breath out.
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8 0
3 years ago
How much thermal energy is added to 10.0 g of ice at −20.0°C to convert it to water vapor at 120.0°C?
Sonbull [250]

Answer:

7479 cal.

31262.2 joules

Explanation:

This is a calorimetry problem where water in its three states changes from ice to vapor.

We must use, the calorimetry formula and the formula for latent heat.

Q = m . C . ΔT

Q = Clat . m

First of all, let's determine the heat for ice, before it melts.

10 g . 0.5 cal/g°C ( 0° - (-20°C) = 100 cal

Now, the ice has melted.

Q = Clat heat of fusion . 10 g

Q = 79.7 cal/g . 10 g → 797 cal

We have water  at 0°, so this water has to receive heat until it becomes vapor. Let's determine that heat.

Q = m . C . ΔT

Q = 10 g . 1 cal/g°C (100°C - 0°C) → 1000 cal

Water is ready now, to become vapor so let's determine the heat.

Q = Clat heat of vaporization . m

Q = 539.4 cal/g . 10 g → 5394 cal

Finally we have vapor water, so let's determine the heat gained when this vapor changes the T° from 100°C to 120°

Q = m . C . ΔT

Q = 10 g . 0.470 cal/g°C . (120°C - 100°C) → 94 cal

Now, we have to sum all the heat that was added in all the process.

100 cal + 797 cal + 1000 cal + 5394 cal + 94 cal =7479 cal.

We can convert this unit to joules, which is more acceptable for energy terms.

1 cal is 4.18 Joules.

Then, 7479 cal are (7479 . 4.18) = 31262.2 joules

6 0
3 years ago
How many moles are in a 62.5-g sample of potassium nitrate (KNO3)?
Reil [10]

Answer:25.3 g of KNO₃ contain 0.25 moles.

Explanation:

7 0
3 years ago
Safety is a concern around electronic equipment of all types. What particular safety hazard may exist A. Laser light B. High vol
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All of the above. If you are going to narrow it down, it would be high voltage and radioactivity.
7 0
3 years ago
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