Answer:
one bond between nitrogen and hydrogen and a double bond between the nitrogen atoms.
Explanation:
H-N=N-H
The original concentration is 5.1 × 10⁹ CFU / ml
In order to attain a countable plate, the number of CFU must be present in between 10 and 200 per ml.
Let us take 0.1 ml and dilute it to 1 ml.
This minimizes the concentration to 5.1 × 10⁹ × 10⁻¹ = 5.1 × 10⁸ CFU/ml
In order to minimize the concentration in between 10 and 200, it can be reduced to 5.1 × 10¹
The final concentration = 5.1 × 10¹ CFU/ml
Initial concentration = 5.1 × 10⁹ CFU/ml
Volume of sample with 5.1 × 10¹ CFU = 5.1 × 10¹ CFU × (1 ml / 5.1 × 10⁹ CFU)
= 1.0 × 10⁻⁸ ml
This is the volume to be taken to obtain countable value, 51 CFU.
Answer:
The products are 4-bromo-2-hexene and 2-bromo-3-hexene
Explanation:
The reaction starts between terminal carbon of of of the double bonds and
. After attaching
to the carbon, one double bond disapears leaveing nearby CH positively charged. This intermediate is a resonance hybrid of two possible structures. Reaction of bromide at one of the carbons gives the 1,2-addition product and at the other carbon gives 1,4-addition product.
Jamal is 2 miles away from his home.
Option B.
<h3><u>Explanation:</u></h3>
The initial distance of Jamal from his home is 8 miles. He needs to return home from his trip.
The speed that Jamal kept was constant for 30minutes and he drove at a speed for 12 miles per hour.
Speed of Jamal = 12 mph.
Time of travel = 30minutes =0.5 hours.
So distance traveled by Jamal =
miles. = 6miles.
Initial distance of Jamal = 8 miles.
So final distance =
miles = 2miles.
So Jamal is 2 miles away from his home.
The equilibrium expression shows the ratio
between products and reactants. This expression is equal to the concentration
of the products raised to its coefficient divided by the concentration of the
reactants raised to its coefficient. The correct equilibrium expression for the
given reaction is:<span>
<span>H2CO3(aq) + H2O(l)
= H3O+(aq) + HCO3-1(aq)
Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>