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Reptile [31]
3 years ago
10

Find the value of x so that the function has the given value. You must show your work for each problem in your notebook to recei

ve full credit.
1. f(x) = 6x+9; f(x) = 21
x = ?

2. g(x) = -1/2x + 3; g(x) = -1
x = ?

If you don't know the answer, then please don't answer at all. Brainly is meant to help others understand the material given. Thank you!
Mathematics
2 answers:
galben [10]3 years ago
7 0

\LARGE{ \underline{ \orange{ \rm{Required \: answer:}}}}

Some functions in variable x is given to us. And the value of the polynomial in x is also given, we need to find the value of x in each case.

GiveN:

  1. f(x) = 6x + 9, f(x) = 21
  2. g(x) = -1/2x + 3, g(x) = -1

What to find?

  • We need to find the value of x in each case.

Step-wise-Step Explanation:

1) <u>f(x) = 6x + 9, f(x) = 21</u>

⇒ f(x) = 21

⇒ 6x + 9 = 21

⇒ 6x = 12

⇒ x = 2

Value of x in this case is <u>2</u><u>.</u>

2) <u>g(x) = -1/2</u><u> </u><u>x</u><u> + 3, g(x) = -1</u>

⇒ g(x) = -1

⇒ -1/2 x + 3 = -1

⇒ -1/2 x = -4

⇒ 1/2 x = 4

⇒ x = 8

Value of x in this case is <u>8</u><u>.</u>

Maru [420]3 years ago
4 0

Answer:

1. The value of x is 2

2. The value of x is 8

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5 0
3 years ago
Read 2 more answers
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
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The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
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Since the length of the normal vector does not change the direction, we simplify the normal vector as
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The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
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expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
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3 0
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