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Aleonysh [2.5K]
3 years ago
13

When a compound such as X2Z4 is created, what would be the correct simplified chemical formula?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

XZ2

Explanation:

There are different ways in which compounds can be represented. Broadly, we have three different types of formula;

- Structural formular: This shows how th atoms in te compound are connected to each other.

- Molecular formular: This shows the actual number of atoms of element present in the compound

- Empirical Formular: This is the simplest formular of a compound. It basically shows the number of atoms in simple ration to each other.

This question requires us to input the empirical formular;

X2Z4

The ratio of the elements is; 2 : 4 which can be simplified into 1 : 2

This means the empirical formular is XZ2

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Balance and find out the coefficients of reactions and products ​
kolezko [41]

Answer:

2, 1, 1, 4.

Explanation:

Hello there!

In this case, for the given chemical reaction:

H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+H_2O\\

We can see how there is one SO4 on the left and two on the right, thus, we add a 2 in front of H2SO4:

2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+H_2O\\

Next, since there are 8 atoms of hydrogen on the left and two on the right, we add a 4 in front of H2O to obtain:

2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O\\

Which is now balanced so the coefficients 2, 1, 1, 4.

Best regards!

6 0
2 years ago
Help me answer this chemistry question. thank you!
Vladimir79 [104]

Answer:

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Explanation:

I think thats the answer in your question

8 0
3 years ago
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
BigorU [14]
Mg reaction with O₂ gas will produce MgO so the equation will be
2Mg+O₂⇒2MgO. (You have to find the equation in order two figure out the number of moles of O₂ that will react with 1 mole of MgO).

The first step is to find the number of moles of Mg in 4.03g of Mg.  You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg.  Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg.  To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂.  From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP.  Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
therefore, 1857mL of O₂ gas will react with 4.03g of Mg.

I hope this helps. Let me know in the comments if anything is unclear.
6 0
3 years ago
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Answer:

Explanation:

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