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Nataliya [291]
3 years ago
7

Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrate

d (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =
Chemistry
1 answer:
Phoenix [80]3 years ago
7 0

The question is incomplete , complete question is :

Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrated (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =31.5

Given: [TZ] = 0.5461 mol/L

Answer:

The concentration of TZ solution in μmol/L is 546 μmol/L

Explanation:

Molarity of the TZ solution = 0.5461 mol/L

This means that 0.5461 moles of TZ are present in 1 L of solution.

Moles of TZ = 0.5461 mol

mol= 1000 \mu mol

0.5461 mol=0.5461\times 1000 \mu mol=546.1 \mu mol

So, the concentration of TZ solution in μmol/L is :

546.1 μmol/L ≈ 546 μmol/L

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A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine
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