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True [87]
3 years ago
11

Solve the triangle. B = 36°, a = 38, c = 18

Mathematics
2 answers:
vovikov84 [41]3 years ago
7 0
Using cosine law.

b= sqrt(38^2 + 18^2 - 2(38)(18) Cos 36)
using calculator solve.
b = sqrt (1444 + 324 - 1106.75)
b = 25.75
nignag [31]3 years ago
6 0

Finishing the answer above:

B=36

a=38

c=18

b=25.7

a-b-c (SSS) {a^2=b^2+c^2-2ab(CosA) [Law of Cosines]

38^2=25.7^2+18^2-2(25.7)(18)(CosA)

1444=660.49+324-925.2(CosA)

1444=984.49-935.2(CosA)

459.51=-935.2(CosA)

-0.491349443969204=CosA

A=119.43

b-B-C (SAA) {(SinC)/c=(SinB/b)} [Law of Sines]

(SinC)/18=(Sin36)/25.7

(SinC)/18=0.022871021489979

SinC=0.411678386819631

C=24.31

A=119.43

B=36

C=24.31

a=38

b=25.7

c=18

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Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot  represents class first. From the first box plot, we get

\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

Second box plot  represents class second. From the second box plot, we get

\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0
3 years ago
Solve each problem and check your answer using estimates. a. $18.79 + $2.11 + ‐$1.92 + $17.28 b. $7.45 + ‐$24.45 + $74.17 + ‐$76
Aneli [31]

The solution to the linear expressions are:

  • a. $36.26
  • b. -$19.35
  • c. $70.38

<h3>Solving linear expressions:</h3>

The solution to linear expression is determined by taking into consideration the arithmetic operations used in each linear expression.

From the information given:

a. $18.79 + $2.11 + ‐$1.92 + $17.28

By rearrangement:

= $18.79 + $2.11 + $17.28 ‐$1.92

= $36.26

b. $7.45 + ‐$24.45 + $74.17 + ‐$76.52

By rearrangement:

= $7.45  + $74.17 ‐ $24.45 ‐ $76.52

= -$19.35

c.  $98.45 − $10.63 + $2.82 − $20.26

By rearrangement:

= $98.45 + $2.82 − $10.63 − $20.26

= $70.38

Learn more about solving linear expressions here:

brainly.com/question/2030026

#SPJ1

7 0
2 years ago
The diagram is not drawn to scale!!<br>pls​
s2008m [1.1K]

Answer:

135°

Step-by-step explanation:

That triangle in the corner is an right angle isosceles triangle as that line the midpoint of both sides :

the base angle of this triangle (x) will be :

180 = 90 + 2x

90 = 2x

x= 45

Angles on a straight line add up to 180. So to work out a :

180 = 45 + a

135 = a

Hope this helped and brainliest please

8 0
2 years ago
Give the domain and range.
yaroslaw [1]

Given:

The graph.

To find:

The domain and range of the graph.

Solution:

The three points on the graph are (-3,3), (0,0) and (3,3).

We know that, domain is the set of input values or x-values. So,

Domain = {-3,0,3}

We know that, Range is the set of output values or y-values. So, elements for range are 3,0,3. But a set contains only distinct elements. So, consider 3 once in range.

Range = {0,3}

Therefore, the correct option is b.

8 0
3 years ago
Describe in your own words what it means to say that integers are closed under addition? (please help I don't get this question)
Naddik [55]

A set  that is closed under an operation or collection of operations is said to satisfy a closure  

property.

For example, the set of even integer is closed under addition, but the set of odd integer is not.  


8 0
3 years ago
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