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Dennis_Churaev [7]
3 years ago
11

A triangle has one side that is 31 inches long and a second side that is 44 inches long. The least possible length of the third

side is_____ in. The greatest possible length of the third side is____in. (Please write the answer in whole numbers only)
BRAINLIEST!!!!!!!
Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

The lowest length on the third side is less that 30 and the largest is between 40 and 30

Step-by-step explanation:

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-2=3(y-2) how do you solve this problem for y​
Ksivusya [100]

Answer:

y= 4/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2=3(y−2)

−2=(3)(y)+(3)(−2)(Distribute)

−2=3y+−6

−2=3y−6

Step 2: Flip the equation.

3y−6=−2

Step 3: Add 6 to both sides.

3y−6+6=−2+6

3y=4

Step 4: Divide both sides by 3.

3y /3 = 4 /3

y= 4/3

Answer:

y= 4/3

8 0
3 years ago
1.Solve the inequality (x-2)(x+1) ≥ 0 .
scoray [572]

Answer:

#1: inequality form: x ≤ –1 or x ≥ 2

interval notion: ( -∞,-1] U [2,∞)

#2: false/no solution

#3: A) point form: (3,9)(-1,1)

equation form: x= 3,y=9 and x= -1,y=1

B)point form: (1,7)(7,1)

equation form: x=1,y=7 and x=7,y=1

Step-by-step explanation:

#1: solve for x by simplifying both sides of the inequality, then isolating the variable.

#2: N/A

#3: solve for the first variable in one of the equations, then substitute the results into the other question.

5 0
3 years ago
I need to show my work & have the correct answer, may someone help , I'm really bad at math
Harlamova29_29 [7]
See picture for answers

4 0
3 years ago
What is the probability of rolling a sum of 3 on a standard pair of six-sided dice?
salantis [7]

To solve this problem, let us recall that the formula for probability is:

Probability = total number of successful events / total events

 

Where in this case, an event is considered to be successful if the sum is 3 on the pair of six sided dice.

 

First, let us calculate for the total number of events. There are 6 numbers per dice, therefore the total number of combinations is:

total events = 6 * 6 = 36

 

Next, we calculate for the total number of combinations that result in a sum of 3. We can identify that there are only two cases that result in sum of 3. That is:

1st case: first dice rolls 1, second dice rolls 2

2nd case: first dice rolls 2, second dice rolls 1

 

Hence, total number of successful events = 2. Therefore the probability is:

Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%

5 0
3 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
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