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2 years ago

SOLVE QUICK PLEASE!! 20 POINTS

Mathematics

1 answer:

PolarNik [594]2 years ago

6 0

Answer:

SA = 384 in²

Step-by-step explanation:

Assuming we're finding surface area:

SA of top of large cube: 8(8) - 4(4) = 48 in²

SA of sides of large cube: 4(8)(8) = 256 in²

SA of exposed faces of small cube: 5(4)(4) = 80 in²

Total = 48 + 256 + 80 = 384 = ∑SA

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Digiron [165]

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3 years ago

A house on the market was valued for 409,000

Nana76 [90]

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3 years ago

Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and

lora16 [44]

Answer:

A'(-3,0), B'(0,-3) and C'(4,7)

Step-by-step explanation:

We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).

We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.

90° clockwise about the origin

Rule: $(x,y)\rightarrow (y,-x)$

Using the rule

The coordinates of A'

$A(0,-3)\rightarrow A'(-3,0)$

The coordinates of B'

$B(3,0)\rightarrow B'(0,-3)$

The coordinates of C'

$C(-7,4)\rightarrow C'(4,7)$

Hence, the vertices of image of triangle is given by

A'(-3,0), B'(0,-3) and C'(4,7)

8 0

3 years ago

Find the value of all trigonometric functions of 135°

Vera_Pavlovna [14]

Answer:

sin (- 135°)= – sin 135°= – sin (1 × 90°+ 45°) = – cos 45° = – 1√2

cos (- 135°)= cos 135°= cos (1 × 90°+ 45°) = – sin 45°= – 1√2

tan (- 135°) = – tan 135° = – tan ( 1 × 90° + 45°) = – (- cot 45°) = 1

csc (- 135°)= – csc 135°= – csc (1 × 90°+ 45°)= – sec 45° = – √2

sec (- 135°)= sec 135°= sec (1 × 90°+ 45°)= – csc 45°= – √2

cot (- 135°) = – cot 135° = – cot ( 1 × 90° + 45°) = – (-tan 45°) = 1

Step-by-step explanation:

hope this helps

5 0

1 year ago

The fractions of -42/-45 and 14/15 are equivalent

FromTheMoon [43]

Yes, that is true, you have to simplify -42/-45 to be able to see if they are equivalant.
$\frac{ - 42}{ - 45} = \frac{14}{15}$

8 0

3 years ago