Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
89.2
Step-by-step explanation:
57.2+32=89.2
I think B not 100%shure ,you could prob go ask this on yahoo and get a bit more help ;) sorry I couldent help more
Step-by-step explanation:
tan30° = Height of person / (Distance away from river bank + river's width) = 1/√3.
Therefore 1.6m / (2m + x) = 1/√3
By cross multiplication, 1.6√3 = 2 + x.
Hence, x ≈ 0.77m.
