7/3x+1/3x=3x+6/3+5/3x
8/3x-5/3x=3x+6/3
3/3x=3x+6/3
x=3x+6/3
x-3x=6/3
-2x=2
-x=2/2
-x=1
x=-1
So with this, you can rewrite the equation as: 
Firstly, solve the multiplication: 
Next, combine like terms, and <u>your answer will be:
</u>
Answer:
Josh is 70% of his fathers height
Step-by-step explanation:
49/70=0.70
0.70 into a percent is 70%
Explanation

When taking derivatives of polynomials, we primarily make use of the power rule.
Power rule.

also, the derivate of a sum is the sum of the derivates
hence

Step 1
apply:

therefore, the answer is
It’s square of pie because the lines don’t match up to you