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Vsevolod [243]
3 years ago
9

Inverse cosine of square root of 3 over 2? cos-1(square root of 3/2)

Mathematics
1 answer:
EastWind [94]3 years ago
8 0
So in your problem which ask to simplify the said trigonometric expression base on their corresponding value and base on my calculation and further formulation, the answer would be 1.849. I hope you are satisfied with my answer and feel free to ask for more if you have question
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The equation for the line g can be written as x-y=9. Line h is parallel to line g and passes through (4,5). What is the equation
Gnoma [55]

Answer:

y = x+1

Step-by-step explanation

The equation in slope intercept form is expressed as y = MX+c

m a the slope

Get the slope of the line

Given the line x-y =9

-y = -x+9

y = x-9

Slope of the line is 1

Since it is parallel to the given line, the slope o the required line is also 1

Substitute m = 1 adnd (4,5) into the point slope form

y-y0 =m(x-x0)

y - 5 = 1(x-4)

y-5 = x-4

y= x-4+5

y = x+1

Hence the required equation is y = x+1

8 0
3 years ago
Number bonds subtract ten
Ymorist [56]
You can arrange it any way as long as you keep the 2 as the very first number
7 0
3 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
Write an equivalent expression to -2(1.5+5)-4(-0.5+3h)
finlep [7]

Answer:

-11-12h

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Based on the data in the table below what is the probability that a given accident involved a driver between the ages of 35 and
Lyrx [107]

Answer:

17.8 D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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