The answer is George washington.
Answer:
6.67408 × 10^-11 m^3 kg^-1 s^-2
Step-by-step explanation:
F = G M 1 M 2 d 2 , where F is the gravitational force between two point masses, M1 and M2; d is the distance between M1 and M2; G is the universal gravitational constant, usually taken as 6.670 × 1011 m3/(kg)(s2) or 6.670 × 10−8 in centimeter–gram–second units. a = F M 1 = G M 2 r 2 .
2:7 = 4:14 because each is equal to 2/7. If you simplify 4:14 by dividing by 2, it simplifies to 2:7.
First we write equation that consist coordinates of center and radius. That formula goes like this:
(x-x1)^2 + (y-y1)^2 = r^2
x and y are coordinates on any point on circle
x1 and y1 are coordinates of center of circle.
r is radius of that circle. now we need to express our values for center and radius andf square binoms and see what matches in our options.
(x-3)^2 + (y-8)^2 = 5^2
x^2 + y^2 -6x -16y +48 = 0
The answer is first option.
If the values are accurate there will be <span>84 Turkish vultures, 14 bald eagles, 28 northern goshawks, and 49 red-tailed hawks.
Jeff's observation accounted for 25 total birds. 175/25 is 7. Multiply the original values by 7 to get an estimate of the total birds in the sanctuary this year.
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