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Nastasia [14]
3 years ago
6

How many ways are there to make a line of 3 teachers and 8 students if a teacher must be at the front of the line

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0
24 possible ways with a different teacher (3) in front
You might be interested in
Mary has 12 video games. She purchases five new video games each month as part of a video game club.
Oxana [17]

Answer:

The answer to your question is:  V = 12 + 5n

Step-by-step explanation:

Data

Video games right now = 12

She purchases 5 video games each month

Equation = ?

# of video games in n month = V

Process

           - Consider the initial amount of video games

                                   V = 12

           - Now, consider the number of video games the buys each month and the months

                                 5n

           - Finally, join both terms

                                  V = 12 + 5n

8 0
3 years ago
James wants to construct a regular hexagon inscribe in a circle with center O and diameter PQ
Brums [2.3K]

Answer:

B. Place the compass at P and draw an arc of length OP across the circle.

Below is the diagram for help.

Step-by-step explanation:

We are given with an already constructed circle of diameter PQ and OP as radius.

To draw a regular hexagon(six-sided), we need to make first cut on the circle of an arc equal to radius of the circle taking any point of the diameter as center

So here, We will consider P as a center and take an arc of length OP and make a cut on the circle.

This would be the first step and James need to repeat the same steps by considering the newly formed cut as center each time.

6 0
3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
Dominic and Terrell plan to start their weekend backpacking trip on Friday at 4:20 P.M, and return home on Sunday at 5:40 A.M. H
Aleonysh [2.5K]

I think the answer is 4.20 hours and minutes planning the last road trip .

6 0
3 years ago
A number decreased by the sum of the number and seven. what is the algebraic expression?​
Aleks04 [339]
The answer would be x-(7+x)
5 0
2 years ago
Read 2 more answers
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