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Maru [420]
3 years ago
8

The ____________ organs produce hormones called estrogen and testosterone. *

Mathematics
2 answers:
Contact [7]3 years ago
7 0
<h2>Reproductive organs</h2>

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

creativ13 [48]3 years ago
7 0
Ovaries

The ____________ organs produce hormones called estrogen and testosterone. *
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What is the circumference of a circle whose diameter is 20?
Sergeeva-Olga [200]

Answer:

C≈62.83

Step-by-step explanation:

Use the formula C=πd

Plug in 20 for d and simplify

You then get 62.8318530718 in a calculator

So, you round it to 62.83

3 0
2 years ago
If you add​ Natalie's age and​ Fred's age, the result is 38. If you add​ Fred's age to 4 times​ Natalie's age, the result is 74.
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2 years ago
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Need help on geometry please right answer only I’m giving out 40 points
Juliette [100K]
Answer: first option 392.699 square feet.


Explanation:

1) The shape of the sidewalk is an ring with exterior radius equal to the radious of the fountain + 5 feet and inner radius equal to the radius of the fountain.

2) The area of such ring is equal to the area of the outer circle less the area of the inner circle (the fountain)

Area of a circle = π × r²

Area of the outer circle: π (10ft +  5 ft)² = π (15 ft)² = 225 π ft²

Area of the inner circle = π (10ft)² = 100 π ft²

Area of the ring  (sidewald) = 225π ft² - 100π ft² = 125π ft² = 392.699 ft²
6 0
3 years ago
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The function f(x) = x^2 is reflected across the x-axis and a stretch factor of 4 is applied to create a second function, g(x). W
Anon25 [30]
C. The vertexes are the same. The functions' vertex (h,k) values were not altered, just a (stretch/compress).
8 0
3 years ago
What is the equation of this graphed line?
barxatty [35]

Answer:

y=-\frac{1}{3}x-5

Step-by-step explanation:

Given:

The two points on the line are:

(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)

Now, for a line with two points on it, the slope of the line is given as:

m=\frac{y_2-y_1}{x_2-x_1}

For the points (x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7), slope is:

m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}

Now, for a line with slope 'm' and a point (x_1,y_1) on it is given as:

y-y_1=m(x-x_1)

Plug in all the values and determine the equation of the line. This gives,

y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5

Therefore, the equation of the line is:

y=-\frac{1}{3}x-5

4 0
3 years ago
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