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3 years ago

(9x3 − 48x2 + 13x + 3) ÷ (x − 5)

Mathematics

1 answer:

lutik1710 [3]3 years ago

4 0

Linked the answer below not sure if it’s right tho

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This is hard, but I really need help!

sukhopar [10]

Please see pic, I'd solved in it.

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4 years ago

What is the product of 3a(8a – 6b)? 24a2 – 6b 24a2 – 6ab 24a2 – 18b2 24a2 – 18ab

pishuonlain [190]

3a(8a – 6b)
= 24a^2 - 18ab

answer is 24a2 – 18ab (the last one)

3 0

3 years ago

Read 2 more answers

-1/7÷-5/9 7/8÷8/9 Show the steps please

Anvisha [2.4K]

So here, the rule "keep,change,switch" works great. so you keep the first fraction the same, switch the division to multiplication and then turn the second fraction upside down
so it looks like this:

-1 * -9= 9
7* 5= 35 = (9/35)

then

7* 9= 63 = (63/64)
8* 8= 64

7 0

3 years ago

F(x, y, z) = z tan−1(y2)i + z3 ln(x2 + 3)j + zk. find the flux of f across s, the part of the paraboloid x2 + y2 + z = 18 that l

Cerrena [4.2K]

$\mathbf F(x,y,z)=z\tan^{-1}(y^2)\,\mathbf i+z^3\ln(x^2+3)\,\mathbf j+z\,\mathbf k$
$\implies\mathrm{div}\mathbf F(x,y,z)=0+0+1=1$

By the divergence theorem, the flux of $\mathbf F$ across the *closed* surface $\mathcal S$ combined with the plane $z=2$ is given by a volume integral over the closed region:

$\displaystyle\iint_{\mathcal S}\mathbf F\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf F\,\mathrm dV$

So in fact, to find the flux over $\mathcal S$ alone, we'll need to subtract the flux of $\mathbf F$ over the planar portion, oriented outward. First, compute the volume integral by converting to cylindrical coordinates:

$x^2+y^2+z=18$
$z=2\implies x^2+y^2=16\implies r^2=16\implies r=4$

$\displaystyle\iiint_{\mathcal R}\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}\int_{z=2}^{z=18-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=128\pi$

If the surface does actually contain $z=2$ , then you can stop here; otherwise, continue.

Now, parameterize the part of the *closed* surface in $z=2$ by

$\mathbf s(r,\theta)=r\cos\theta\,\mathbf i+r\sin\theta\,\mathbf j+2\,\mathbf k$

where $0\le r\le4$ and $0\le\theta\le2\pi$ . We get a surface element

$\mathrm d\mathbf S=(\mathbf s_r\times\mathbf s_\theta)\,\mathrm dr\,\mathrm d\theta=(r\,\mathbf k)\,\mathrm dr\,\mathrm d\theta$

We don't need to worry about the first two components of

and so the surface integral over this region is

$\displaystyle\iint_{z=2\,\land\,x^2+y^2\le16}\mathbf F\cdot\mathrm d\mathbf S=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}2r\,\mathrm dr\,\mathrm d\theta=32\pi$

Then the total flux over $\mathcal S$ alone is $(128-32)\pi=96\pi$ .

4 0

3 years ago

An automobile manufacturer wants to find out what types of product-related problems its customers are experiencing. The best met

Alik [6]

Data collection involving the types of product-related problems a manufacturer's customers are experiencing is more suitable to make use of qualitative data collection. This is because the type of data you are interested in is more subjective and open-ended. The best method to gather the data is through survey/questionnaire.

4 0

3 years ago