Question

Will give brainliest!! Using the measurements of the shapes.. determine the area and perimeter of the irregular polygon.

Answer 1

Answer:

$p=28.2\:\text{units},\\A=40.2\:\text{square units}}$

Step-by-step explanation:

The irregular shape's area consists of the sum of the areas of all the shapes that make it up.

Area of pink triangle: $\frac{1}{2}\cdot 3 \cdot 3=4.5$

Area of purple square: $3^2=9$

Area of green quadrilateral: $3\cdot 2.9=8.7$

Area of blue triangle: $\sqrt{10.25(10.25-8.5)(10.25-6)(10.25-6)}=17.99989$

Therefore, the area of the irregular polygon is $4.5+9+8.7+17.99989\approx \boxed{40.2\:\text{square units}}$.

The perimeter of the irregular polygon consists of certain shred sides from the four polygons that make up:

$p=3+3+3+4.2+3+6+6=\boxed{28.2\:\text{units}}$