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IRISSAK [1]
3 years ago
15

Will give brainliest!! Using the measurements of the shapes.. determine the area and perimeter of the irregular polygon.

Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer:

p=28.2\:\text{units},\\A=40.2\:\text{square units}}

Step-by-step explanation:

The irregular shape's area consists of the sum of the areas of all the shapes that make it up.

Area of pink triangle: \frac{1}{2}\cdot 3 \cdot 3=4.5

Area of purple square: 3^2=9

Area of green quadrilateral: 3\cdot 2.9=8.7

Area of blue triangle: \sqrt{10.25(10.25-8.5)(10.25-6)(10.25-6)}=17.99989

Therefore, the area of the irregular polygon is 4.5+9+8.7+17.99989\approx \boxed{40.2\:\text{square units}}.

The perimeter of the irregular polygon consists of certain shred sides from the four polygons that make up:

p=3+3+3+4.2+3+6+6=\boxed{28.2\:\text{units}}

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