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2 years ago

Midpoints...........

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

5 0

Answer:

$op = 2$

Step-by-step explanation:

$look \: picture \\ \\ pls \: mark \: as \: brainliest$

telo118 [61]2 years ago

3 0

Answer:

OP = 2

Step-by-step explanation:

please mark me brainliest and 5 star

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Help asap pleasee, I'LL GIVE BRAINLIEST FOR THIS QUESTION

pochemuha

Answer:

C is the answer

Step-by-step explanation:

2π/2 = π

8 0

2 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

In circle M with m \angle LMN= 98m∠LMN=98 and LM=18LM=18 units, find the length of arc LN. Round to the nearest hundredth.

Feliz [49]

Answer:

To the nearest hundredth, this is 30.79 units

Step-by-step explanation:

To find the length of the arc, we simply apply the length of arc formula

Mathematically, that would be;

theta/360 * 2 * pi * r

Theta here is 98

r is 18 units

So the length of the arc will be;

98/360 * 2 * 22/7 * 18

= 30.7876 units

to the nearest hundredth, this is;

30.79 units

5 0

2 years ago

PLEASE HELP!! Algebra 2 Review !!

Kamila [148]

Answer:

$\frac{28-3i}{26}$

Step-by-step explanation:

For #2, remember that $i=\sqrt{-1}$ , so $i^{2}=-1$ Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)= $a^2-b^2$ . Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number $a+bi$ , where a and b are any numbers, the conjugate is always $a-bi$ . Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this: