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iren [92.7K]
3 years ago
9

Midpoints...........

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
5 0

Answer:

op = 2

Step-by-step explanation:

look \: picture \\  \\ pls \: mark \: as \: brainliest

telo118 [61]3 years ago
3 0

Answer:

OP = 2

Step-by-step explanation:

please mark me brainliest and 5 star

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Evaluate - x2 + y2 where x= -1 and y=3
o-na [289]

Answer:

8

Step-by-step explanation:

-(-1)^2+(3)^2=-1+9\\=8

3 0
3 years ago
Select the correct product.
vfiekz [6]
The correct answer is:  [A]:  " 2x³  +  7x² + 12x − 8 " .
______________________________________________________

Explanation:
__________________________________________
Given:  
__________________________________________
" (x² + 4x + 8) (2x − 1) "  ;  Find the product: 

↔  " (2x − 1) (x² + 4x + 8) "  ; 
__________________________________________

Note:  " (a + b) (c + d + e) = ab + ad + ae + bc + bd + ae " .
__________________________________________

  →  " (2x − 1) (x² + 4x + 8) = 

      (2x * x²) + (2x * 4x) + (2x *8)  + (-1 * x²) + (-1 * 4x) + (-1 * 8) ; 

 =    2x³ + 8x² + 16x + (-1x²) + (-4x) + (-8) ; 

=     2x³ + 8x² + 16x − x² − 4x − 8) ; 

→ Combine the "like terms" :

        + 8x² − x² =  + 7x² ; 

        + 16x − 4x =  + 12x ; 
_______________________________________________________
And rewrite the expression:
_______________________________________________________
   →  " 2x³  +  7x² + 12x − 8 " ;

   → which is:  Answer choice:  [A]:  " 2x³  +  7x² + 12x − 8 " .
_______________________________________________________
7 0
3 years ago
Simplify 5 to the 3rd power and 2.5 to the 2nd power
Eddi Din [679]
5*5*5=125
2.5*2.5= 6.25
8 0
4 years ago
A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen
serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

Sample size = 580

Defective units = 8

Number of picks = 2

a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

P=\frac{7}{579}=0.121

b) The probability that both are defective is given by:

P=\frac{8}{580}*\frac{7}{579}= 0.000167

c) The probability that both are acceptable is given by:

P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

P=\frac{6}{578}}= 0.0104

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

P=\frac{7}{578}= 0.01211

f) The probability that all three are defective is given by:

P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731

7 0
4 years ago
Evaluate start fraction 2 over 3 end fractionx for x = three-fourths
Umnica [9.8K]

Answer:

A

Step-by-step explanation:

7 0
4 years ago
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