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spayn [35]
3 years ago
6

What is the value of p if the expression 4(n+7) is equivalent to (n+p)4?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

p = 7

Step-by-step explanation:

set the expressions = to each other

4(n+7) = 4(n+p)

distribute the 4 on both sides(multiplying the numbers on the inside)

4n+28 = 4n+4p

subtract the 4n from the right and left

28 = 4p

divide by 4

p = 7

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PLEASE ALSO EXPLAIN HOW TO SOLVE THIS. 20 POINTS
eimsori [14]
B.) Hibiscus Street 

The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept

So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.

Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
 
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C.) Oak Street 
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D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.

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6 0
3 years ago
Anuhea has horses and ducks on her farm. There is a total of 15 animals. She counts a total of 36 animal legs.
LuckyWell [14K]

so whats the question?


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3 years ago
What is the quadratic regression equation for the data set? ​ ​ ​ <br><br> PLEASEE HELP ME
Soloha48 [4]
You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

Computing this, you'd find that

\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

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8 0
3 years ago
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Ulleksa [173]
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8 0
3 years ago
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professor190 [17]

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This is the amount of minutes that have elapsed.

Then, you convert the minutes to hours by dividing by 60:

17,152.9/60=285.8816667 (285 hours and 52 minutes)

This gives you how many hours and minutes have elapsed.

Finally, you calculate the number of days that have elapsed by dividing 285 by 24 (there are 24 hours in a day):

285/24=11.875 (11 days and 21 hours).

Put all of the amounts together to get the final answer:

11 days, 21 hours, and 52 minutes have elapsed

7 0
3 years ago
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