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3 years ago

Find the least common multiple of 36,6 ,3

Mathematics

1 answer:

Lerok [7]3 years ago

4 0

-- least common multiple of 36, 6, 3 = 36

- it is the smallest number divisible by all three.

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Solve for R. 3 + 3r > 9

Nostrana [21]

Answer:

r > 2

Step-by-step explanation:

9-3 = 6

6/3 = 2

Have a good day :)

7 0

3 years ago

You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 are blue. What is the probability that

Brrunno [24]

It would be $\frac{10}{38}$ , or, in simplest form, $\frac{5}{19}$ .

You get this by adding all the marbles to find the total number of marbles. 10+7+12+9, which equals 38.

You have 10 red marbles out of 38 total, so that is represented by $\frac{10}{38}$ !

5 0

3 years ago

Read 2 more answers

A leprechaun places a magic penny under a girl's pillow. The next night there are 2 magic pennies under her pillow. Each night

11Alexandr11 [23.1K]

Answer:

tn = 2097152 pennies
tn = 20971.52 dollars.

Step-by-step explanation:

A surprisingly large amount of money.

The question is "Does the amount of money just double or do the previous amounts add to the present amount?"

I think it just doubles. Not only that, but she can't spend any of it until night 22 is reached.

tn = a*2^(n - 1)
a = 1 She starts with 1 penny.
n = 22
tn = 1*2^(22 - 1)
tn = 1*2^21
tn = 2097152 pennies
tn = 20971.52 dollars.

8 0

3 years ago

(03.05 MC) Solve the rational equation x divided by 2 equals x squared divided by quantity x minus 2 end quantity, and check for

ycow [4]

Answer:

x = 0 and x = -2 are solutions of the given rational equation.

Step-by-step explanation:

We must solve the following rational equation:

$\frac{x}{2} = \frac{x^{2}}{x-2}$

Now we present the procedure:

1) $\frac{x}{2} = \frac{x^{2}}{x-2}$ Given

2) $x\cdot (x-2) = 2\cdot x^{2}$ Compatibility with multiplication/Existence of the multiplicative inverse/Definition of division/Modulative property.

3) $x^{2}-2\cdot x = 2\cdot x^{2}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

4) $x^{2} + 2\cdot x = 0$ Compatibility with addition/Existence of the additive inverse/Modulative property/Reflexive property

5) $x \cdot (x+2) = 0$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

6) $x = 0\, \lor\, x = -2$ Result

Now we check the rational equation with each root:

x = 0

$\frac{x}{2} = \frac{x^{2}}{x-2}$

$\frac{0}{2} = \frac{0^{2}}{0-2}$

$0 = \frac{0}{-2}$

$0 = 0$

x = 0 is a solution of the rational equation.

x = -2

$\frac{x}{2} = \frac{x^{2}}{x-2}$

$\frac{-2}{2} = \frac{(-2)^{2}}{-2-2}$

$-1 = -1$

x = -2 is a solution of the rational equation.

4 0

3 years ago

-1/2y=1/2x+5 and y=2x+2

Anettt [7]

I assume this is the intersection of two lines, i.e. -1/2y is (-1/2)y. Please tell me if it's really -1/(2y).

(-1/2)y=(1/2)x+5

Multiplying both sides by -2

y = - x - 10

The other equation is

y = 2x + 2

We can equate them to find the meet

y = - x - 10 = 2x + 2

-3x = 12

x = -4

y = 2x + 2 = -6

Check: (-1/2)y=3, (1/2)x+5=3, equal, good

2x+2=2(-4)+2=-6=y, good

Answer: x=-4, y=-6

6 0

3 years ago