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Novosadov [1.4K]
3 years ago
10

Can Someone help me with this question I don't exactly know how to do it ;-;

Mathematics
1 answer:
Lelechka [254]3 years ago
6 0
x^3= \frac{64}{27}  \\  \\ x^3= \left( \frac{4}{3} \right) ^3 \\  \\ x= \frac{4}{3}
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The anwser is one and  two tenths
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True of false: 1+1 has the same answer as 1x1
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Help me i dont know what i am doing at all
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3 years ago
Find the area of the following shape. You must show all work to receive credit.
Artist 52 [7]

By comparing the given shape with easier ones like triangles and rectangles we will see that the area of the shape is 8 square units.

<h3>How to simplify the shape.</h3>

So the given shape is a little bit complex, but you can actually see that it is a triangle with a base of 8 units with a height of 4 units, where a rectangle of 2 in by 3 in was removed, and also removed a triangle of height of 2 inches and base of 2 inches.

Remember that:

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Then the area of the given shape is:

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If you want to learn more about areas, you can read:

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5 0
2 years ago
Rationalize the denominator !!!
satela [25.4K]

Answer:

\frac{1\cdot \left(4+\sqrt{3}\right)}{\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)}\\

1\cdot \left(4+\sqrt{3}\right)=4+\sqrt{3}

\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right) = 13

= \frac{4+\sqrt{3}}{13}

x = 4

y = 3

z = 13

4 0
1 year ago
Read 2 more answers
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