X=0 y=-2
y=0 x=4
The shortest distance has to be the perp bisector from origin to the midpoint of the line.
midpoint =(2,-1) and distance from the (0,0) origin is sqrt(5) hence, sqrt(5).
Step-by-step explanation:
v=6t-6
integrating
s= 3t^2 -6t +k
5=3(1)^2 -6(1) +k
5-3+6=k
k=8
s(t) = 3t^2 -6t +8
Answer:
5 pigs
Step-by-step explanation:
A farmhouse shelters 16 animals, some are pigs, and some are ducks. Altogether there are 42 legs. How many pigs are there?
Let us represent:
Number of pigs = x
Number of ducks = y
Our system of equations is given as:
A farmhouse shelters 16 animals, some are pigs, and some are ducks.
x + y = 16...... Equation 1
x = 16 - y
Altogether there are 42 legs.
Ducks have 2 legs(feet) , pigs have 4 legs,
4x + 2y = 42..... Equation 2
We substitute
16 - y for x in Equation 2
Hence:
4(16 - y) + 2y = 42
64 - 4y + 2y = 42
Collect like terms
- 4y + 2y = 42 - 64
-2y =- 22
y = -22/-2
y = 11 ducks
Solving for x.
x = 16 - y
x = 16 - 11
x = 5 pigs
Therefore, we have 5 pigs
Answer:
57.8125% or approx. 57.8%
Step-by-step explanation:
There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.
Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.
Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:
0.75 * 0.75 * 0.75 = 
= 0.421875
From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...
1 - 0.421875 = 0.578125
...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.
Answer: approx. 57.8% or 57.8125%
825 - 625i
Hope it’s right
Best luck with your studying
