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GREYUIT [131]
3 years ago
8

HELP ME FAST WILL GIVE BRAINLY

Mathematics
1 answer:
muminat3 years ago
3 0

the total of marbles = 16 + 10 +12 =38

A) white : blue = 16/10 = 8/5

B) red : total = 12/38 = 6/19

Step-by-step explanation:

1. find the total of marbles

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Latoya earns $25.05 for 3 hours of tutoring. How much money does latoya earn each hour?
charle [14.2K]

Answer:

$8.35 per hour

Step-by-step explanation:

Take the dollars and divide by the hours to determine the dollars per hour

25.05/3

$8.35 per hour

6 0
3 years ago
Find the domain and range of <img src="https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B2x%7D%7B1%20%2B%20x%5E2%7D" id="TexFormula1"
Vinvika [58]
Hi,

Work:

Equation;

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8 0
3 years ago
Help please! Ty!! ----
Tresset [83]

Answer:

5 4/9

Step-by-step explanation:

9 x 5 + 4= 5 4/9

BRAINLIEST PLZAESE

3 0
3 years ago
If using the method of completing the square to solve the quadratic equation
lubasha [3.4K]

Answer:

31.25

Step-by-step explanation:

The general form of a complete square would be (x + a)^2 + b

Given an equation of X^2 + 15X + 25 = 0,

the idea is to reduce it into the form if (X + C)^2

which can be expanded into X^2 + 2XC + C^2

In this case 15 will be our 2C So our c will be 7.5.

Substituting in these numbers,

We have X^2 + 15X + (7.5)^2 = 0

However our original equation has 25 for its C^2, thus

we need to add 31.25 in order to get (7.5)^2

<u>FYI</u>

The final completed form will be (X + 7.5)^2 - 31.25

5 0
3 years ago
When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
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