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3 years ago

Which given congruence is still needed to prove that LMO = NMO by AAS?

Mathematics

1 answer:

GalinKa [24]3 years ago

5 0

The correct answer is C

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Use a Calculator!

Semenov [28]

The answer is 60 I think

7 0

3 years ago

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Find the following ratios. Write each answer as a fraction and as a decimal rounded to four decimal places.

Alona [7]

Answer:

$y = 56.6208$

Step-by-step explanation:

Given

The attached triangle

Required

Find y

To find y, we make use of the relationship between sides lengths 44 & y and angle 39

The relationship is:

$cos(39) = \frac{44}{y}$

i.e.

$cos(\theta) = \frac{Adjacent}{Hypotenuse}$

Make y the subject

$y = \frac{44}{cos(39)}$

$y = \frac{44}{0.7771}$

$y = 56.6208$ -- approximated

5 0

3 years ago

For the function f(x)= 3x+7, what is f(3)

Lesechka [4]

The answer will be
f(3)=3(3)+7
=9+7
=16

6 0

3 years ago

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Find dy/dx using first principle<br>x+1/x

JulsSmile [24]

Answer:

The derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

Step-by-step explanation:

The first principle is given by:

$f'(x)=\frac{dy}{dx}=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

The function here is:

$f(x)=x+\frac{1}{x}$

Now, using the first principle we have:

$f'(x)=lim_{h\rightarrow 0}\frac{(x+h)+\frac{1}{(x+h)}-x-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h+\frac{1}{(x+h)}-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h-\frac{h}{x(x+h)}}{h}$

$=lim_{h\rightarrow 0}\frac{h(1-\frac{1}{x(x+h)})}{h}$

$=lim_{h\rightarrow 0}1-\frac{1}{x(x+h)}$

$=1-\frac{1}{x^{2}}$

Therefore, the derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

I hope it helps you!

6 0

2 years ago

What is the DOMAIN of the following relation? {(-5,4), (-4,2), (0,2), (1,3), (2,4)}

weeeeeb [17]

Answer:

{-5, -4, 0, 1, 2}

Step-by-step explanation:

The domain is the inputs or the x values

{-5, -4, 0, 1, 2}

3 0

3 years ago

Read 2 more answers