Answer:
Numerals
Dimensions
Extension Lines
Arrowheads
Dimension Figures
Isometric Dimensioning
Orthographic Dimensioning
If a drawing is to be complete, so that the object represented by the drawing can be made as intended by the designer, it must tell two complete stories. It tells this with views, which describe the shape of the object, and with dimensions and notes, which give sizes and other information needed to make the object.
Therefore, your next step is to learn the basics of dimensioning. In that way, you will understand not only how to interpret a drawing to get the information you need, but also how to dimension your sketches so that they can be used to communicate size information to others.
Numerals
It may seem a bit basic, but a few exercises with the shapes of numbers come before dimensioning. The reason for such a review is simply that incorrectly or carelessly made numbers on a drawing or sketch can easily be misinterpreted by someone on the job. That can be costly.
Therefore, the study of numbers forms is justified.
The number forms presented here have been determined to be the most legible, and are used by industry nationwide. The United States standardized 1/8” vertical
Explanation:
Explanation:
Look at the drawings and decide which view is missing. Front? Side? Top? Then draw it
Answer:
Signal the driver behind you when it is safe to pass by turning on your four-way emergency flashers.
Avoiding casualties is the top priority when driving, the other choices given do not put whether there are cars in the other lane into consideration, therefore making them incorrect. Signaling the driver when it is safe gives you the time and them the gateway to pass, making a nice interaction keep you both alive.
Answer:
The original length of the specimen is found to be 76.093 mm.
Explanation:
From the conservation of mass principal, we know that the volume of the specimen must remain constant. Therefore, comparing the volumes of both initial and final state as state 1 and state 2:
Initial Volume = Final Volume
πd1²L1/4 = πd2²L2/4
d1²L1 = d2²L2
L1 = d2²L2/d1²
where,
d1 = initial diameter = 19.636 mm
d2 = final diameter = 19.661 mm
L1 = Initial Length = Original Length = ?
L2 = Final Length = 75.9 mm
Therefore, using values:
L1 = (19.661 mm)²(75.9 mm)/(19.636 mm)²
<u>L1 = 76.093 mm</u>
