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Korolek [52]
3 years ago
13

You work for a printing company, and you realize that your colleague sent incorrect price quotes to a client. You begin to write

an e-mail to the client to apologize for the mistake. You want to remedy the situation without criticizing your colleague. The following sentence is an excerpt from your e-mail: "Incorrect information was included in the initial document we sent you."
Engineering
1 answer:
xxTIMURxx [149]3 years ago
4 0

Answer:

The sentence excerpted from the e-mail uses passive voice.  

Given the  purpose of your message, this voice is appropriate.

Explanation:

Because the objective is to remedy the situation a passive voice is great because it emphasizes the action and the object instead of the subject.

We want to emphasize the document and the incorrect information, not our colleague.

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A 2.2-kg model rocket is launched vertically and reaches an altitude of 70 m with a speed of 30 m/s at the end of powered flight
kirill115 [55]

Answer:

r_b= (30.8\hat{i} + 69.96 \hat{j}) m

Explanation:

given,

mass = 2.2 kg

altitude(r₀) = (70 j) m

speed = 30 m/s

m_a = 0.77 kg

m_b =1.43 kg

part A strike ground (r_a)= (80 i) m

t = 6 s

r = r_0 + v_ot-\dfrac{1}{2}gt^2

r = 60\hat{j} + (30\hat{j})\times 6-\dfrac{1}{2}\times 9.8 \times 6^2

r = 63.6 j m

by conservation of energy

mr = m_ar_a+m_br_b

2.2\times 63.6\hat{j} = 0.77\times (-80 \hat{i})+2\times r_b

r_b= (30.8\hat{i} + 69.96 \hat{j}) m

8 0
3 years ago
Yield and tensile strengths and modulus of elasticity . with increasing temperature. (increase/decrease/independent)
meriva

Answer:

Yield strength, tensile strength decreases with increasing temperature and modulus of elasticity decreases with increasing in temperature.

Explanation:

The modulus of elasticity of a material is theoretically a function of the shape of curve plotted between the potential energy stored in the material as it is loaded versus the inter atomic distance in the material. The temperature distrots the molecular structure of the metal and hence it has an effect on the modulus of elasticity of a material.

Mathematically we can write,

E(t)=E_o[1-a\frac{T}{T_m}]

where,

E(t) is the modulus of elasticity at any temperature 'T'

E_o is the modulus of elasticity at absolute zero.

T_{m} is the mean melting point of the material

Hence we can see that with increasing temperature modulus of elasticity decreases.

In the case of yield strength and the tensile strength as we know that heating causes softening of a material thus we can physically conclude that in general the strength of the material decreases at elevated temperatures.

6 0
3 years ago
Complete the following sentence. The skills and content of several subject areas were combined to form a new field known as a me
Svetlanka [38]

Answer:

The answer is "discipline" , I was doing the same thing a minute ago. I hope this anwser is helpful! ^^

Explanation:

5 0
3 years ago
Read 2 more answers
Consider a circular grill whose diameter is 0.3 m. The bottom of the grill is covered with hot coal bricks at 961 K, while the w
soldi70 [24.7K]

Answer:

Step 1

Given

Diameter of circular grill,   D = 0.3m

Distance between the coal bricks and the steaks,  L = 0.2m

Temperatures of the hot coal bricks,  T₁ = 950k

Temperatures of the steaks, T₂ = 5°c

Explanation:

See attached images for steps 2, 3, 4 and 5

4 0
3 years ago
The engine of a 2000kg car has a power rating of 75kW. How long would it take (seconds) to accelerate from rest to 100 km/hr at
Delvig [45]

Answer: 10.29 sec.

Explanation:

Neglecting drag and friction, and at road level , the energy developed during the time the car is accelerating, is equal to the change in kinetic energy.

If the car starts from rest, this means the following:

ΔK = 1/2 m*vf ²

As Power (by definition) is equal to Energy/Time= 75000 W= 75000 N.m/seg, in order to get time in seconds, we need to convert 100 km/h to m/sec first:

100 (Km/h)*( 1000m /1 Km)*(3600 sec/1 h)= 27,78 m/sec

Now, we calculate the change in energy:

ΔK= 1/2*2000 Kg. (27,78)² m²/sec²= 771,728 J

<h2>If P= ΔK/Δt, </h2><h2>Δt= ΔK/P= 771,728 J / 75,000 J/sec= 10.29 sec.</h2>
4 0
3 years ago
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