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Ganezh [65]
3 years ago
5

Please help no files

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

x =1 for the first problem

and for second question

Step-by-step explanation:

Let's solve your inequality step-by-step.

|2x+5|>0.5

Solve Absolute Value.

|2x+5|>0.5

We know either2x+5>0.5or2x+5<−0.5

2x+5>0.5(Possibility 1)

2x+5−5>0.5−5(Subtract 5 from both sides)

2x>−4.5

2x2>−4.52(Divide both sides by 2)

x>−2.25

2x+5<−0.5(Possibility 2)

2x+5−5<−0.5−5(Subtract 5 from both sides)

2x<−5.5

2x2<−5.52(Divide both sides by 2)

x<−2.75

Answer:

x>−2.25 or x<−2.75

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Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be
Rina8888 [55]
This is a combination problem.

Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.

The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.

This is the formula I used because the order is not important and repetition is not allowed. 

Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.

numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960

Combination = 39,916,800 / 120,960 = 330

There are 330 ways that the instructor can choose 4 students for the first group


8 0
3 years ago
Read 2 more answers
If a varies jointly as b and c,
Alborosie

Given:

a varies jointly as b and c.

a=6 when b=2 and a=3.

To find:

The variation constant and the equation of variation.

Solution:

a varies jointly as b and c.

a\propto bc

a=kbc              ...(i)

Where, k is the constant of proportionality.

a=6 when b=2 and a=3.

6=k(2)(3)

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4 0
2 years ago
Find the product (-3) • (1.2)<br><br> A. 4.5 <br><br> B. -3.6<br><br> C. -4.6<br><br> D. 5.3
NikAS [45]
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4 0
3 years ago
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Please help me find n. 1/3=n+3/4
raketka [301]

Answer:

-5/12

Step-by-step explanation:

Let's solve your equation step-by-step.

1 /3  = n +  3 /4

Step 1: Flip the equation.

n +  3 /4  =  1/ 3

Step 2: Subtract 3/4 from both sides.

n+  3 /4  −  3/4   =  1/ 3  −  3 /4

n=  −5 /12

7 0
3 years ago
The weight of a radioactive isotope was 96 grams at the start of an experiment. After one hour, the weight of the isotope was ha
zimovet [89]
The starting weight of the radioactive isotope = 96 grams

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After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.

This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.

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We can plot the sequence using the above equation. The graph is attached below.

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3 years ago
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