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Zepler [3.9K]
3 years ago
9

State whether the given equation or function is linear. Write yes or no. Explain your reasoning. 5x4 + 5y = 9

Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer:

The given equation is NOT linear.

Step-by-step explanation:

5x^4+5y = 9

The given equation is NOT linear.

Reason:

A linear equation is defined as the equation for the straight line, where the degree of variables involved is always equal to 1.

But in the given equation :

Degree if x = 4

and degree of y = 1

As degree of x≠ 1 so, the given equation is not linear,

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A model that has 4 points and 6 lines containing exactly two points <br>​
OleMash [197]

Answer:

4=point

6=line

4+6=10

the answer is 10

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2 years ago
Janet's car will go 462 miles on 16.5 gallons of gas. How many miles will it take to drive 2719 miles
ololo11 [35]
2719/462 x 16.5 = 97.10714gallons which is approximately 97 gallons.
7 0
2 years ago
How do you find a subtotal
jolli1 [7]

This is the hardest question I've answered all day.

One way to find a sub-total is by *simply* adding everything together, and a example would be below, buy yeah, you just add everything together.

For example:

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5 0
3 years ago
Annie earns $7.50 per hour working after school. She needs at least $185 for a stereo system. Write an inequality that describes
VMariaS [17]
185 < 7.50 (x)

x = hours
4 0
3 years ago
Read 2 more answers
Find an equation of the plane with x-intercept a, y-intercept b, and z-intercept c. What is the distance between the origin and
Elenna [48]

Answer:

The equation is:

(1/a)x + (1/b)y + (1/c)z = 1

Step-by-step explanation:

The direction vector between the points (a, 0, 0) and (0, b, 0) is given as:

<0 - a, b - 0, 0 - 0>

<-a, b, 0> .....................(1)

The direction vector between (0, 0, c) and (0, b, 0) is given as:

<0 - 0, b - 0, 0 - c>

= <0, b, -c> .....................(2)

To obtain the direction vector that is normal to the surface of the plane, we take the cross product of (1) and (2).

Doing this, we have:

<-a, b, 0> × <0, b, -c> = <-bc, -ac, -ab>

To find the scalar equation of the plane we can use any of the points that we know. Using (0, b, 0), we have:

(-bc)x + (-ac)y + (-ab)z = (-bc)0 + (-ac)b + (-ab)0

(bc)x + (ac)y + (ab)z = (ac)b

Dividing both sides by abc, we have:

(1/a)x + (1/b)y + (1/c)z = 1

3 0
3 years ago
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