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alukav5142 [94]
3 years ago
9

The titanium content of an alloy is being studied in the hope of ultimately increasing the tensile strength. An analysis of six

recent heats chosen at random produces the following titanium contents. 9.7% 7.4% 5.9% 7.7% 7.5% 8.9% What is the value of the test statistic, if the alternative hypothesis is the mean titanium content is greater than 9.5%?
Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

Tstatistic = - 3.068

Step-by-step explanation:

Given the data: 9.7% 7.4% 5.9% 7.7% 7.5% 8.9%

Mean titanium > 9.5%

Test statistic :

(m - μ) / (s/√n)

From the data: obtain the sample mean and standard deviation

From the data given ;

Calculate the same mean and standard deviation :

Using calculator :

Sample mean (m) = ΣX / n

Sample size (n) = 6

m = 47.1 / 6 = 7.85

Standard deviation (s) :

Using calculator = 1.317

Hence,

(m - μ) / (s/√n)

Tstatistic = (7.85 - 9.5) / (1.317/√6)

Tstatistic = - 1.65 / 0.5376629

Tstatistic = - 3.068

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The surface areas of two similar solids are 340 yd² and 1,158 yd². The volume of the larger solid is 1,712 yd³. What is the volu
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Brainest for best answer only 5 mins left show your work
Kamila [148]

Answer:

Step-by-step explanation:

Problem One

Perimeter is in meters not square meters. The equation is

2*(6.8+x) + 2*12.5= 47                Remove the brackets. Combine like terms  

13.6 + 2x + 25 = 47

38.6 + 2x = 47                            Subtract 38.5 from both sides

2x = 47 - 38.6  

2x = 8.4                                      Divide by 2

x = 4.2

Answer D

Problem 2

This problem is asking that you calculate the perimeter of a swimming pool.

The two semicircles on the ends make a whole circle.

The diameter of the semicircles is obtained from the difference of the two given lengths.

The rectangle has a length of 12. The length of the rectangle and the 2 semicircles is 16. The difference is 4. You could divide this by 2 to get the radius. I would just leave it as the diameter.

So the perimeter is pi*d + 2 * 12 [there are 2 lengths]

Perimeter = 4*pi + 24

Perimeter = 12.56 + 24

Perimeter = 36.56

Answer A

Problem 3

This is the circle inside the square.

The radius of the circle = 9

The diameter of the circle and the length of square's side = 2*9 = 18

The area of the square = s^2  where s = 18

The area of the square = 18^2 = 324

The area of the circle = pi * 9^2 = 3.24 * 81 = 251.34

The area of the Shaded area = 324 - 251.34 = 69.66

Answer C

Problem 4

b1 = 5

b2 = 11.5

h = 4.5

Formula

Area = (b1 + b2 ) * 4.5/2

Area =  (5 + 11.5) * 4.5 /2

Area = 16.5 * 4.5 / 2

Area = 74.25/2

Area = 37.125

Answer D

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3 years ago
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