Answer:
![y^2=\frac{1}{8}x](https://tex.z-dn.net/?f=y%5E2%3D%5Cfrac%7B1%7D%7B8%7Dx)
Step-by-step explanation:
The focus lies on the x axis and the directrix is a vertical line through x = 2. The parabola, by nature, wraps around the focus, or "forms" its shape about the focus. That means that this is a "sideways" parabola, a "y^2" type instead of an "x^2" type. The standard form for this type is
![(x-h)=4p(y-k)^2](https://tex.z-dn.net/?f=%28x-h%29%3D4p%28y-k%29%5E2)
where h and k are the coordinates of the vertex and p is the distance from the vertex to either the focus or the directrix (that distance is the same; we only need to find one). That means that the vertex has to be equidistant from the focus and the directrix. If the focus is at x = -2 y = 0 and the directrix is at x = 2, midway between them is the origin (0, 0). So h = 0 and k = 0. p is the number of units from the vertex to the focus (or directrix). That means that p=2. We fill in our equation now with the info we have:
![(x-0)=4(2)(y-0)^2](https://tex.z-dn.net/?f=%28x-0%29%3D4%282%29%28y-0%29%5E2)
Simplify that a bit:
![x=8y^2](https://tex.z-dn.net/?f=x%3D8y%5E2)
Solving for y^2:
![y^2=\frac{1}{8}x](https://tex.z-dn.net/?f=y%5E2%3D%5Cfrac%7B1%7D%7B8%7Dx)
Answer:
-2x + 5y = 25
Step-by-step explanation:
Answer:
m∠QPR = 20°
Step-by-step explanation:
If we make a sketch of the triangle, it will be observed, that line R bisects angle P.
Considering Triangle, ΔQPS;
∠QPS=107∘
Considering triangle, QPR;
∠QPR=9x-115∘
Considering triangle, RPS;
∠RPS=4x+27∘
Thus, ∠RPS + ∠QPR = ∠QPS
4x+27° + 9x-115° = 107°
13x - 88° = 107∘
13 x = 107∘ + 88∘
13x = 195°
x = 195°/13
x = 15°
m∠QPR = 9x - 115°
= (9 x 15) - 115°
= 135° - 115°
= 20°
Therefore, m∠QPR = 20°
Given: y=x^3 and y=343
So, 343=x^3
Cube root both sides which will get rid of the cube on the right side of the equation
You are left with the cube root of 343. Which equals 7.
7*7*7=343
X=7
Answer:
22.8
Step-by-step explanation:
![a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C20%5E%7B2%7D%20%2B11%5E%7B2%7D%20%3Dx%5E%7B2%7D%20%5C%5C400%2B121%3Dx%5E%7B2%7D%5C%5C%5Csqrt%7B521%7D%20%3Dx%5C%5C%5C%5Cor%5C%5C%5C%5C22.8%20%3D%20x)