The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:
<em>y</em> = <em>x</em>² - 9<em>x</em> → d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9
When <em>x</em> = 4, the function takes on a value of
<em>y</em> = 4² - 9•4 = -20
and the derivative is
d<em>y</em>/d<em>x</em> (4) = 2•4 - 9 = -1
Then use the point-slope formula to get the equation of the tangent line:
<em>y</em> - (-20) = -1 (<em>x</em> - 4)
<em>y</em> + 20 = -<em>x</em> + 4
<em>y</em> = -<em>x</em> - 24
The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is
<em>y</em> - (-20) = 1 (<em>x</em> - 4)
<em>y</em> + 20 = <em>x</em> - 4
<em>y</em> = <em>x</em> - 24
Answer:
it is not
Step-by-step explanation:
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(X-7)(x-7)
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Answer:
Hope i helped :)
Step-by-step explanation:
8) T-V =24
24 -6 =18
2x-18 =18
2x=0
x= 0/2
x=0
9)
*LMK
*L-K=x+3
*L-M=6x-10
*M-K= 3x-3
L-M + M-K = 6x -10 + 3x -3 = 9x -13
10 and 11)
Both lines are horizontal
both lines consist of intervals due to having 2 points on one line making it a distance between 2 points.
they are also concurrent lines because more then 3 lines pass through one point
they are also intersecting lines because they cross over each other