All categories

3 years ago

Find the slope of the line that passes through (4,-2) and (2,4) please

Mathematics

2 answers:

Lyrx [107]3 years ago

5 0

The slope would be -3

Ksju [112]3 years ago

3 0

Answer: -3

Step-by-step explanation:

To find the slope of a line we need two coordinates on the line. Any two coordinates will suffice. We are basically measuring the amount of change of the y-coordinate, often known as the rise, divided by the change of the x-coordinate, known the the run. The calculations in finding the slope are simple and involves nothing more than basic subtraction and division.

You might be interested in

John has 2456 pennies in his coin collection he has the same number of pennies in each of the three boxes estimate to the neares

Keith_Richards [23]

If I read correctly, 2456 pennies needs to be divided simply by 3 then rounded to the nearest hundredth. So you would do 2456/3 3 goes into 24 how many times? Then 3 goes into 5 how many times, then continue the pattern. Once you've gotten a decimal to the thousandth, round the number to the hundredth and there you go

5 0

3 years ago

Which is greater 8/10 or 63/100 ?

bazaltina [42]

8/10 is greater than 63/100, it is grater because when u change them into a percentage 8/10 is higher

4 0

3 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

3 years ago

Substract 8 times the sum of a and b from 9y

erastovalidia [21]

Answer:

Step-by-step explanation:

according to the question ur equation is

9y-8(a+b)

9y-8a-8b

6 0

2 years ago

Read 2 more answers

Can someone please help me find the measure of angle ABO?

lara [203]

Answer:

m<ABO = 22 deg

Step-by-step explanation:

A tangent intersects a circle at the point of tangency making a right angle with the radius drawn to that point. That means that <BAO is a right angle and measures 90 deg. That makes the other two angles of the triangle complementary with a sum of 90 deg.

m<O + m<B = 90

68 + m<B = 90

m<B = 22

Answer: m<ABO = 22 deg

3 0

3 years ago