4¾=19/4 and 11⅞=95/8.
Width=area/length=95/8÷19/4=95/8×4/19=5/2=2½ft.
The limit does not exist. Because its left limit when x < 0 is -9, and the right limit is 2, which is not equal.
Answer:
<em>(3*105
)+(2*104
)+(0*103)
+(4*102
)+(0*101
)+(0*100)</em>
Step-by-step explanation:
(3*105
)
+(2*104
)
+(0*103)
+(4*102
)
+(0*101
)
+(0*100)
Answer:
(1) The sample mean is = 6.98, the standard deviation is = 4.53 (2) The pint estimate difference is = 20.2 (3) The confidence interval limits are $ 15943.6 and $24456.4
Step-by-step explanation:
Solution
(A) The first step is to compute the mean sample and the standard deviation for private and public colleges.
Thus,
The mean and private colleges is computed as follows:
The mean and private colleges = The sum of derivation/The total number of observation
x= 42.5
The standard deviation is S₁ = 6.9806 = √∈ (xi - x)²/n-1
The mean of public colleges y =22.3
Standard deviation S₂ = 4.5323 = √∈ (yi - y)²/n-1
Thus,
S₁ = 6.98
S₂ =4.53
(b) We find the point estimate of the difference between two population means
Thus,
x -y = 42.5 -22.3
=20.2
Therefore, the annual cost is =$20,200
Note: Kindly find an attached copy of the option c and the complete question stated above.
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