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Elanso [62]
3 years ago
11

How do you multiple 14.5×6.5×6.5?

Mathematics
2 answers:
BARSIC [14]3 years ago
7 0
Multiple 14.6 x 6.5 then multiply the answer to that by 6.5
mario62 [17]3 years ago
4 0

\textsf{Hey there!}

\mathsf{How\ do\ you\ multiply\ 14.5\times6.5\times6.5?}

\bullet\ \textsf{First you have to line up your decimals (If its easier for you break down the equation)}

\mathsf{14.5\times6.5\times6.5}\\\mathsf{14.5\times6.5=\underline{94.25}}\\\mathsf{94.25\times6.5=\underline{612.625}}\\\\\boxed{\boxed{\mathsf{Thus, your\ answer\ is: \boxed{\boxed{\huge\text{\bf{612.625}}}}}}}\checkmark

\mathsf{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

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Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el
sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

= 30/100 \ of \ x\\= 0.3x

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

0,3475x = 37

x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

= 106.48-79.86\\= 26.62

3 0
3 years ago
F(x) = -x^3+ 6x – 7 at x = 2
vodomira [7]

Answer:

f(2)= -4

Step-by-step explanation:

f(x)= -x^3 + 6x - 7

f(2) = -2^3 + 6*2 - 7

f(2)= -8 +12 -7

f(2)= 3-7

f(2)= -4

4 0
3 years ago
Please Help!!!!!!!<br> Simplify (√5)(3√5).
kirill [66]

The answer is 15

multiply 3sqrt(25)

3*5=15

7 0
3 years ago
M/J Grade 8 Pre-Algebra-PT-FL-1205070-003
Andreas93 [3]

Answer:

Following are the description of the given course code:

Step-by-step explanation:

The given course code is Pre-Algebra, which is just an introduction arithmetic course programs to train high school in the Algebra 1. This course aims to strengthen required problem solving skills, datatypes, equations, as well as graphing.

  • In this course students start to see the "big picture" of maths but also understand that mathematical, algorithmic, and angular principles are intertwined to form a basis for higher mathematics education.
  • The duration of this code is in year and it is divided into two levels. In this, code it includes PreK to 12 Education Courses , with the general mathematics .
5 0
3 years ago
List the factors to find the GCF of 24 and 66.
Gala2k [10]
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
factors of 66:  1, 2, 3 ,6, 11, 22, 66 

GCF: 6
8 0
3 years ago
Read 2 more answers
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