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Nezavi [6.7K]
3 years ago
14

Laura sees a horse pulling a buggy. She wonders how it can accelerate if the action of the horse pulling the cart would causes a

n equal and opposite reaction of the cart pulling on the horse. Which explanation best answers her question​
Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

The net forces exerted on the horse and cart are not the same, so they are not balanced forces.

Step-by-step explanation:

Please see the Newton's 2nd Law which states  that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.

As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.

If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.

If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.

Fofino [41]3 years ago
6 0

Answer:

The net forces exerted on the the horse and cart are not the same, so they are not balanced forces.

Step-by-step explanation:

According to Newton's 2nd Law, an object accelerates if there is a net or unbalanced force on it. For a body to accelerate, two factors are involved which are the mass of the object and the net force acting upon the body.  In this situation, there is just one force exerted on the cart i.e: the force that the horse exerts on it. The cart accelerates because the horse pulls on it. The amount of acceleration can be calculated by dividing the net force on the cart by its mass.

In this scenario, we can clearly see the actions of the pull and push forces. The pull force brings an object closer while the push moves an object away from something. The cart pulls the horse backwards, and the ground pushes the horse forward. They both work in opposite directions. The net force is determined by the relative sizes of these two forces.

If the push force is greater(i.e the ground pushes harder on the horse than the cart pulls), then there is a net force in the forward direction, and the horse accelerates forward. But if the pull force is greater( the cart pulls harder on the horse than the ground pushes), then there is a net force in the backward direction, and the horse accelerates backward.

If the force that the cart exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.

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What is the equation of a line that passes through the points (-3, 4) and (2,8)?
ziro4ka [17]

Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,4) and (2,8) in the above formula, we get;

m=\frac{8-4}{2+3}

m=\frac{4}{5}

Thus, the slope of the line is m=\frac{4}{5}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-3,4) and m=\frac{4}{5} in the above formula, we have;

y-4=\frac{4}{5}(x+3)

y-4=\frac{4}{5}x+\frac{12}{5}

     y=\frac{4}{5}x+\frac{12}{5}+4

     y=\frac{4}{5}x+\frac{32}{5}

Thus, the equation of the line is y=\frac{4}{5}x+\frac{32}{5}

6 0
3 years ago
Enter a phrase for the expression
Nina [5.8K]

Answer:

The quotient of x and 11.

Step-by-step explanation:

Given:

\frac{x}{11}

Required:

Write the expression in words

Solution:

In the expression given, we have the numerator which is the dividend (x), and the denominator which is the divisor (8).

So, we are dividing x into 8 parts.

A quotient is the result you get when you divide the dividend by the divisor.

✅In describing the expression in words, we would use the following phrase:

The quotient of x and 11.

The dividend is mentioned first before the dividend.

8 0
3 years ago
Why is (x-3) NOT a factor of x3+2x2-5x-6
ivolga24 [154]

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Step-by-step explanation:

Given expression is:

x^3+2x^2-5x-6

We have to check if x-3 is a factor of given expression

In order for x-3 to be a factor of expression, we have to put x-3 = 0 => x=3 in expression.

If the expression is zero at x=3 then x-3 is a factor of expression otherwise not.

So putting x=333 in expression

=(3)^3+2(3)^2-5(3)-6\\= 27+2(9) - 15-6\\= 27+18-15-6\\= 45-21\\=24 \neq 0

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/4228574
  • brainly.com/question/4279146

#LearnwithBrainly

8 0
4 years ago
Find the coordinates of
alexira [117]

Answer:(6,-2)

Step-by-step explanation:

M is the midpoint of AB then ,

M = \frac{A+B}{2}

5=\frac{x+4}{2}     ,     -2=\frac{y-2}{2}

10=x+4  ,      -4=y-2

x=6          ,      y= -2

so, B= (6,-2)

3 0
3 years ago
What is the complement of 13 degrees
AlekseyPX
Since complementary angles add up to 90 degrees, we simple take 90=13+c and simplify it to c=77°
8 0
3 years ago
Read 2 more answers
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