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wariber [46]
3 years ago
6

What is the average rate of change of f(X)=-6(2)^x from x=-1 to x=2

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0
Ok done. Thank to me:>

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Help! Does anyone know which answer is correct?
guapka [62]
What you do is solve all of the equations  using the coordinates given for l and m
6 0
3 years ago
Plzz help me i really need help guys
OverLord2011 [107]

Answer:

Figure 1: 226 ft^{2}

Figure 2: 111 mm^{2}

Step-by-step explanation:

For the first figure, you will split it into two rectangles. You would do 28 x 7 for the first rectangle and get 196. Then, you would do 6 x 5 for the second rectangle and get 30. You would then add these two numbers and get the area of 226 ft^{2}}.

For the second figure, you split it into one triangle and two rectangles. For the triangle, you would do 3 x 6 and then divide that by 1/2, since it is a triangle, and you get 9. For the first rectangle, you would do 10 x 7 and you would get 70. For the final rectangle, you would do 8 x 4 and get 32. You would then add all these numbers up and get the area of 111 mm^{2}.

4 0
3 years ago
X = -135°, cos 2x = _______
Ket [755]

Answer:

cos 2 x=1-sin^2 x

Step-by-step explanation:

x=-135°

cos 2x=cos (-270)=cos (-270+360)=cos 90=0

or cos 2x=1-2sin ²x=1-2(sin (-135))²

=1-2(-sin 135)²

=1-2(sin 135)²

=1-2(sin (180-45))²

=1-2(sin²45)

=1-2 (\frac{1}{\sqrt{2}})²

=1-1

=0

4 0
3 years ago
The following table shows the height of a plant at different ages.
Travka [436]

Answer:

No

Step-by-step explanation:

because the age is 4 so 3*4=12 correct then 12 * 4 = 48 not 35 therefore No!!

5 0
3 years ago
From a point 18 feet from the base of a tower, a wire is stretched to an attachment 40 feet up the tower. A right triangle with
Tamiku [17]
To find the length of the wire, use the Pythagorean theorem

a^2 + b^2 = c^2
18^2 + 40^2 = c ^2
324 + 1600 = c^2
1924 = c^2
44 = c

The wire is approximately 44 feet.
8 0
4 years ago
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