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nadya68 [22]
2 years ago
14

A/b=2/5 and b/c=3/8 find a/c​

Mathematics
1 answer:
m_a_m_a [10]2 years ago
3 0

Answer:

\frac{a}{c} = \frac{3}{20}

Step-by-step explanation:

\frac{a}{c} = \frac{a}{b} × \frac{b}{c} = \frac{2}{5} × \frac{3}{8} = \frac{6}{40} = \frac{3}{20}

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Find the value of p for which x = -2, y = -1 is a solution of linear equation 5x + 2py = 2p.​
Rom4ik [11]
I think p=4
How I solved it:
5(-2)+2p+2(-1)=2p
-10+2p+-2=2p So cross out last
-2p -2p 2p:)
= -10+2p+-2
+10 +10 Cross out the 10
= 2p=8
= divide both sides by 2p
= 2p/2= 8/2
= cross out the 2.
= which leaves
= p=4 we get 4 because we divide 8 to 2:)


I don’t know if I’m right but yea...



8 0
3 years ago
(6.04)The equation of the line of best fit of a scatter plot is y = 6x − 9. What is the slope of the equation?
Ghella [55]
Y=mx+b
m=slope

given
y=6x-9
m=6

the slope is 6
5 0
3 years ago
A conditional statement is logically equivalent to a biconditional statement. True False pls help i have a test and i was absent
andreyandreev [35.5K]

Answer:

false.

Step-by-step explanation:

A conditional statement is something like:

If P, then Q.

This means that if a given proposition P is true, then another proposition Q is also true.

An example of this is:

P = its raining

Q = there are clouds in the sky.

So the conditional statement is

If its raining, then there are clouds in the sky.

A biconditional statement is:

P if and only if Q.

This means that P is only true if Q is true, and Q is only true if P is true.

So, using the previous propositions we get:

Its raining if and only if there are clouds in the sky.

This statement is false, because is possible to have clouds in the sky and not rain.

(this statement implies that if there are clouds in the sky, there should be rain)

Then we could see that for the same propositions, the conditional statement is true and the biconditional statement is false.

Then these statements are not logically equivalent.

The statement is false.

3 0
3 years ago
Lcm of (x-2)(x+3) and 10(x+3)^2
Arte-miy333 [17]
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:

(x - 2)(x + 3)          10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²

Answer: LCM is 10(x - 2)(x + 3)²


8 0
3 years ago
What is the solution to the equation?
Gelneren [198K]

Answer:

Hello,

answer B

2

Step-by-step explanation:

\dfrac{2}{x} -\dfrac{x}{x+5} =\dfrac{10}{x^2+5x} \\\\we\ suppose\ x\neq 0\ and\ x\neq -5\\\\\text{Reducing to the same denominator}\\\dfrac{2(x+5)-x^2}{x(x+5)} =\dfrac{10}{x^2+5x} \\\\Simplify\ by\ x^2+5x\\\\2x+10-x^2=10\\\\-x^2+2x=0\\\\-x(x-2)=0\\\\roots\ are\ 2 \ and\ 0\ (to\ be\ excluded)\\\\Root=2\\

3 0
3 years ago
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