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Leona [35]
3 years ago
9

A rectangle with an area of 47 m² is dilated by a factor of 7. What is the area of the dilated rectangle? Do not leave your answ

er as a fraction.
Mathematics
2 answers:
PolarNik [594]3 years ago
8 0
Area of rectangle = lb = 47 m^2

Dilation by a factor of 7 results in 1/7 l x 1/7 b = 1/49 lb = 1/49 (47) = 47/49 = 0.9592
Levart [38]3 years ago
7 0

Answer:

The area of the dilated rectangle is 28\ m^{2}

Step-by-step explanation:

we know that

If two figures are similar, then the scale factor squared is equal to the ratio of its areas

Let

z------> the scale factor

x-----> the area of dilated rectangle

y-----> the area of the original rectangle

so

z^{2}=\frac{x}{y}

In this problem we have

z=7

y=(4/7)\ m^{2}

substitute and solve for x

7^{2}=\frac{x}{4/7}

x=49*(4/7)=28\ m^{2}


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Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
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Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

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Then

648 \times 10^7 = 6,480,000,000


There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

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3 years ago
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Answer:

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Step-by-step explanation:

8 0
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