Question

A rectangle with an area of 47 m² is dilated by a factor of 7. What is the area of the dilated rectangle? Do not leave your answer as a fraction.

Answer 1

Area of rectangle = lb = 47 m^2

Dilation by a factor of 7 results in 1/7 l x 1/7 b = 1/49 lb = 1/49 (47) = 47/49 = 0.9592

Answer 2

Answer:

The area of the dilated rectangle is $28\ m^{2}$

Step-by-step explanation:

we know that

If two figures are similar, then the scale factor squared is equal to the ratio of its areas

Let

z------> the scale factor

x-----> the area of dilated rectangle

y-----> the area of the original rectangle

so

$z^{2}=\frac{x}{y}$

In this problem we have

$z=7$

$y=(4/7)\ m^{2}$

substitute and solve for x

$7^{2}=\frac{x}{4/7}$

$x=49*(4/7)=28\ m^{2}$