Answer:
1) Sam only interviewed five people out of his entire ELA class, so he doesn't have a very wide demographic to study
2) All of these people were Sam's friends, so they might all have similar interests or only enjoy certain things, and that doesn't allow for a wide range of data collection
You plug in numbers -3 to 3 into the x variable of the equation and then plot those points
y = -2x
X = -3 y = (-2)(-3) = 6
X = -2 y = (-2)(-2) = 4
X = -1 y = (-2)(-1) = 2
X = 0 y = (-2)(0) = 0
X = 1 y = (-2)(1) = -2
X = 2 y =(-2)(2) = -4
X = 3 y = (-2)(3) = -6
In case that looks a little cluttered here are the points to graph:
(-3, 6) (-2, 4) (-1, 2) (0, 0) (1, -2) (2, -4) (3, -6)
Answer:
the last one
Step-by-step explanation:
In the last one, it takes all of the numbers in the one parentheses and distributes it to the 0.5.
Look at the picture. (sorry for the messy writing)
Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
14 days = 2 weeks so
14 times 3 = 42
