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Arlecino [84]
3 years ago
9

The chart show the masses and velocities of two colliding objects that stick together after a collision.

Mathematics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:1,500 kg • m/s

Step-by-step explanation:

took the quiz

inessss [21]3 years ago
6 0

Answer: C

Step-by-step explanation: I know my answer is correct because,according to the law of conservation you will half yo think about what you are doing so what i did was look at the velocity first so 15 and -10 . but then i realized that i could multiply 150 by -10 even though it is a negative number and i got 1,500    

                         

HOPE THIS HELPS ;D ;D ;P sorry for all the faces and i took the test

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
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Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0
3 years ago
Plz help me 20 point
ddd [48]
Hey friend your answer

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Answer:

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Step-by-step explanation:

(-21 + -24 + -37 + -52 + - 56)/5 = -38

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