Consider the expression below.
(- 6)(x+ 2)
For (x - 6)(x + 2) to equal ,either (X - 6) or (x+2) must equal____
The values of x that would result in the given expression being equal to 0, in order from least to greatest
V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
x² - 4x - 12 = 0
Factor the left side: (x + 2) · (x - 6) = 0
The equation is true if either factor is zero.
If (x + 2) = 0 then x = -2 .
If (x - 6) = 0 then x = 6 .