5(3)+2
15+2
17 monies
Just plug the amount of games in for n
Multiply the coefficients and the powers of 10 with each other:
![(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})](https://tex.z-dn.net/?f=%283.8%20%5Ctimes%2010%5E%7B-6%7D%29%20%5Ctimes%20%282.37%20%5Ctimes%2010%5E%7B-3%7D%29%20%3D%20%283.8%5Ctimes2.37%29%20%5Ctimes%20%2810%5E%7B-6%7D%20%5Ctimes10%5E%7B-3%7D%29)
The numeric part simply yields
![3.8\times2.37 = 9.006](https://tex.z-dn.net/?f=%203.8%5Ctimes2.37%20%3D%209.006%20)
As for the powers of 10, you have to add the exponents, using the rule
![a^b \times a^c = a^{b+c}](https://tex.z-dn.net/?f=%20a%5Eb%20%5Ctimes%20a%5Ec%20%3D%20a%5E%7Bb%2Bc%7D%20)
So, we have
![10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}](https://tex.z-dn.net/?f=%2010%5E%7B-6%7D%20%5Ctimes10%5E%7B-3%7D%20%3D%2010%5E%7B-6-3%7D%20%3D%2010%5E%7B-9%7D)
So, the final answer is
![9.006\times 10^{-9}](https://tex.z-dn.net/?f=%209.006%5Ctimes%2010%5E%7B-9%7D%20)
I believe the answer is B
Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
Justin walked 3 miles north and 6 miles west so his distance from the start is the square root of 9+36 or 45. This can be simplified to 3√5.
Tina walked 2 miles south and 4 miles east so her distance from the starting point is the square root of 4 + 16 or 20. This can be written as 2√5.
If we add these two distances together we get 5√5. Hence, Justin and Tina are 5√5 miles away from each other.
Answer:
1. mean 2. mean absolute deviation
Step-by-step explanation: